C语言实现扫雷小游戏简单版

本文实例为大家分享了C语言实现扫雷小游戏的具体代码,供大家参考,具体内容如下

在vs2019创建新项目,然后添加两个源文件test.c和game.c,接着创建一个头文件game.h。

test.c:

#include "game.h"

void game()

{

char mine[ROWS][COLS] = { 0 };

char show[ROWS][COLS] = { 0 };

InitBoard(mine, ROWS, COLS, '0');

InitBoard(show, ROWS, COLS, '*');

SetMine(mine, ROW, COL);

//DispalyBoard(mine, ROW, COL);

DispalyBoard(show, ROW, COL);

FindMine(mine, show, ROW, COL);

}

void menu()

{

printf("**************************\n");

printf("****** 1.play ******\n");

printf("****** 0.exit ******\n");

printf("**************************\n");

}

int main()

{

int input = 0;

srand((unsigned int)time(NULL));

do

{

menu();

printf("请输入:");

scanf("%d", &input);

switch (input)

{

case 1:

game();

break;

case 0:

printf("退出游戏\n");

break;

default:

printf("输入错误,请重新输入\n");

break;

}

} while (input);

return 0;

}

game.c:

#include "game.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)

{

int i = 0;

for (i = 0; i < rows; i++)

{

int j = 0;

for (j = 0; j < cols; j++)

{

board[i][j] = set;

}

}

}

void DispalyBoard(char board[ROWS][COLS], int row, int col)

{

int i = 0;

for (i = 0; i <= 9; i++)

{

printf("%d ", i);

}

printf("\n");

for (i = 1; i <= row; i++)

{

int j = 0;

printf("%d ", i);

for (j = 1; j <= col; j++)

{

printf("%c ", board[i][j]);

}

printf("\n");

}

}

void SetMine(char board[ROW][COL], int row, int col)

{

int count = EASY_COUNT;

while (count)

{

int x = rand() % row + 1;

int y = rand() % col + 1;

if (board[x][y] != '1')

{

board[x][y] = '1';

count--;

}

}

}

int GetMineCount(char mine[ROWS][COLS], int x, int y)

{

return (mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y - 1] +

mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1] - 8 * '0');

}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)

{

int x = 0;

int y = 0;

int win = 0;

while (win<row*col-EASY_COUNT)

{

printf("请输入要排查的坐标:");

scanf("%d%d", &x, &y);

if (x >= 1 && x <= row && y >= 1 && y <= col)

{

if (mine[x][y] == '1')

{

printf("很遗憾,你被炸死了\n");

DispalyBoard(mine, ROW, COL);

break;

}

else

{

int count = GetMineCount(mine, x, y);

show[x][y] = count + '0';

DispalyBoard(show, ROW, COL);

win++;

}

}

else

{

printf("坐标非法,请重新输入\n");

}

}

if (win == row * col - EASY_COUNT)

{

printf("排雷成功\n");

}

}

game.h:

#pragma once

#include <stdio.h>

#include <stdlib.h>

#include <time.h>

#define ROW 9

#define COL 9

#define EASY_COUNT 10

#define ROWS ROW+2

#define COLS COL+2

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);

void DispalyBoard(char board[ROWS][COLS], int row, int col);

void SetMine(char board[ROWS][COLS], int row, int col);

void FindMine(char mine[ROW][COL], char show[ROW][COL], int row, int col);

运行效果如图:

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

以上是 C语言实现扫雷小游戏简单版 的全部内容, 来源链接: utcz.com/p/246670.html

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