C语言模拟实现简单扫雷游戏

本文指的扫雷是简单模拟电脑中的游戏" title="扫雷游戏">扫雷游戏,但以我目前的水平,也就只能在黑框中实现

test.c

#include<stdio.h>

#include<stdlib.h>

#include<time.h>

#include "game2.h"

void menu()

{

printf("********* welcome ********\n");

printf("**********1.play**********\n");

printf("**********0.exit**********\n");

}

enum Option

{

EXIT,

PLAY

};

void game()

{

int x = 0;

int y = 0;

int i = 0;

int win = 0;

char mine[ROWS + 2][COLS + 2] = { 0 };

char show[ROWS + 2][ROWS + 2] = { 0 };

init_board(mine, ROWS + 2, COLS + 2, '0');

init_board(show, ROWS + 2, COLS + 2, '*');

//display(mine, ROWS + 2, COLS + 2);#define _CRT_SECURE_NO_WARNINGS

//display(show, ROWS + 2, COLS + 2);

mine_set(mine, ROWS + 2, COLS + 2);

display(mine, ROWS + 2, COLS + 2);

while (win<ROWS*COLS - DEFAULT_COUNT)

{

for (i = 0; i <= win; i++)

{

printf("请输入坐标:>");

scanf("%d%d", &x, &y);

//合法性判断

if ((x>0) && (x <= ROWS) && (y > 0) && (y <= COLS))

{

if ((i == 0) && (mine[x][y] == '1'))

{

(mine[x][y] = '0') ;

}

if (mine[x][y] == '1')

{

printf("很遗憾,你被炸死了\n");

break;

}

else

{

int count = 0;

win++;

count = get_mine_num(mine, x, y);

show[x][y] = count + '0';

display(show, ROWS + 2, COLS + 2);

}

}

else

{

printf("输入错误请重新输入\n");

}

}

if (win >= ROWS*COLS - DEFAULT_COUNT)

{

printf("恭喜你,扫雷成功\n");

}

}

}

int main()

{

int input = 0;

srand((uint_t)time(NULL));

do

{

menu();

printf("请选择:>");

scanf("%d", &input);

switch (input)

{

case PLAY:

game();

break;

case EXIT:

break;

default:

printf("输入错误,请重新输入\n");

break;

}

} while (input);

system("pause\n");

return 0;

}

game.c

#define _CRT_SECURE_NO_WARNINGS 1

#include "game2.h"

#include<stdlib.h>

#include<stdio.h>

#include<string.h>

void init_board(char arr[ROWS + 2][COLS + 2], int row, int col,char ch)

{

memset(arr, ch, sizeof(char) * row * col);

}

void display(char arr[ROWS + 2][COLS + 2], int row, int col)

{

int i = 0;

int j = 0;

printf(" ");

for (i = 0; i < col - 2; i++)

{

printf("%d ", i + 1);

}

printf("\n");

for (i = 0; i < row - 2; i++)

{

printf("%2d ", i + 1);

for (j = 0; j < col - 2; j++)

{

printf("%c ", arr[i + 1][j + 1]);

}

printf("\n");

}

}

void mine_set(char arr[ROWS + 2][COLS + 2], int row, int col)

{

int x = 0;

int y = 0;

int count = DEFAULT_COUNT;

while (count)

{

x = rand() % 10 + 1;

y = rand() % 10 + 1;

if (arr[x][y] != '1')

{

arr[x][y] = '1';

count--;

}

}

}

int get_mine_num(char arr[ROWS + 2][COLS + 2], int x, int y)

{

return (arr[x][y - 1] - '0') +

(arr[x - 1][y - 1]-'0')- +

(arr[x - 1][y]-'0') +

(arr[x - 1][y + 1]-'0') +

(arr[x][y + 1]-'0') +

(arr[x + 1][y + 1]-'0') +

(arr[x + 1][y]-'0') +

(arr[x + 1][y - 1]-'0');//返回周围雷的个数

}

game.h

#ifndef __GAME_H__

#define __GAME_H__

#define ROWS 10

#define COLS 10

#define DEFAULT_COUNT 20

typedef unsigned int uint_t;//类型重命名

#include<string.h>

#include<stdio.h>

#include<time.h>

#include<stdlib.h>

void init_board(char arr[ROWS + 2][COLS + 2], int row, int col,char ch);//初始化

void display(char arr[ROWS + 2][COLS + 2], int row, int col);

void mine_set(char arr[ROWS + 2][COLS + 2], int row, int col);//放雷

int get_mine_num(char arr[ROWS + 2][COLS + 2], int row, int col);//统计坐标周围雷的个数

#endif //__GAME_H__

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

以上是 C语言模拟实现简单扫雷游戏 的全部内容, 来源链接: utcz.com/p/244578.html

回到顶部