计算3点(x,y)的曲率
我有一个二维欧几里德空间。给出了三点。
例如(p2是中间点):
Point2D p1 = new Point2D.Double(177, 289);Point2D p2 = new Point2D.Double(178, 290);
Point2D p3 = new Point2D.Double(178, 291);
现在,我想计算这三个点的曲率。
double curvature = calculateCurvature(p1, p2, p3);
这该怎么做?是否存在现有方法(没有Java外部库)?
- 曲率:https : //en.wikipedia.org/wiki/曲率
- Menger曲率:https: //en.wikipedia.org/wiki/Menger_curvature
回答:
对于Menger
Curvature,该公式就在Wikipedia文章中:
curvature = 4*triangleArea/(sideLength1*sideLength2*sideLength3)
您到底尝试了哪个代码?
给定3分,计算这4个值应该并不难。
以下是一些有用的方法:
/** * Returns twice the signed area of the triangle a-b-c.
* @param a first point
* @param b second point
* @param c third point
* @return twice the signed area of the triangle a-b-c
*/
public static double area2(Point2D a, Point2D b, Point2D c) {
return (b.x-a.x)*(c.y-a.y) - (b.y-a.y)*(c.x-a.x);
}
/**
* Returns the Euclidean distance between this point and that point.
* @param that the other point
* @return the Euclidean distance between this point and that point
*/
public double distanceTo(Point2D that) {
double dx = this.x - that.x;
double dy = this.y - that.y;
return Math.sqrt(dx*dx + dy*dy);
}
没有更多的事情要做。警告:area2
根据点的方向(顺时针或逆时针)返回带符号的双精度型。
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