用C语言实现三子棋
本文实例为大家分享了用C语言实现三子棋的具体代码,供大家参考,具体内容如下
三子棋含义:
三子棋是黑白棋的一种。三子棋又叫九宫棋、圈圈叉叉、一条龙、井字棋等。将正方形对角线连起来,相对两边依次摆上三个双方棋子,只要将自己的三个棋子走成一条线,对方就算输了。但是,有很多时候会出现和棋的情况。图例如下:
基本思路:
1.创建用户交互菜单界面
2.初始化棋盘
3.显示棋盘面板(为了不重复显示棋盘,使用清屏操作)
4.用户落子
5.判断胜负
6.电脑随机正确落子
7.判断胜负
(在每次写程序之前,可以向如下图所示,写出思路或伪代码)
创建多文件项目:
写代码之前,首先建立三个文件,以方便后序代码更加完整清晰地呈现。
1.创建用户交互菜单界面
void Meau(){
printf("+------ meau ----------+\n");
printf("|---- 1.play --------|\n");
printf("|---- 0.quit --------|\n");
printf("+----------------------+\n");
}
2.初始化棋盘
使用宏定义,将棋盘中的内容初始化为空。
static void InitBoard(char board[][COL], int row, int col){
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
board[i][j] = INIT;
}
}
}
3.显示棋盘面板
为了不重复显示棋盘,使用清屏操作,使得每次现实的棋盘只有一张。
通过不断调试,使得最终界面,与预期所需界面一致。
static void ShowBoard(char board[][COL],int row,int col){
system("cls");//清屏操作
printf(" ");
for (int i = 0; i < col; i++){
printf(" %3d", i + 1);
}
printf("\n----------------\n");
for (int i = 0; i < row; i++){
printf("%-2d", i + 1);
for (int j = 0; j < col; j++){
printf("| %c ", board[i][j]);
}
printf("\n----------------\n");
}
}
4.用户落子
落子只能落在为空的位置上,所以在落子前需要判空,若为空,则落子,否则提示重新落子。
static void PlayerMove(char board[][COL], int row, int col){
int x = 0;
int y = 0;
while (1){
printf("please enter your postion<x,y>: ");
scanf("%d %d", &x, &y);
if (x<1 || x>3 || y<1 || y>3){
printf("Postion Error!");
continue;
}
if (board[x - 1][y - 1] == INIT){
board[x - 1][y - 1] = WHITE;
break;
}
else{
printf("Postion Is Not Empty!\n");
}
}
}
5.电脑随机正确落子
使用随机数,在正确位置落子。
static void ComputerMove(char board[][COL], int row, int col){
while (1){
int x = rand() % row;
int y = rand() % col;
if (board[x][y] == INIT){
board[x][y] = BLACK;
break;
}
}
}
6.判断胜负
static char IsEnd(char board[][COL], int row, int col){
for (int i = 0; i < row; i++){
if (board[i][0] == board[i][1] && \
board[i][1] == board[i][2] && \
board[i][0] != INIT){
return board[i][0];
}
}
for (int j = 0; j < col; j++){
if (board[0][j] == board[1][j] && \
board[1][j] == board[2][j] && \
board[0][j] != INIT){
return board[0][j];
}
}
if (board[0][0] == board[1][1] && \
board[1][1] == board[2][2] && \
board[0][0] != INIT){
return board[0][0];
}
if(board[0][2] == board[1][1] && \
board[1][1] == board[2][0] && \
board[1][1] != INIT){
return board[1][1];
}
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
if (board[i][j] == INIT);
return NEXT;
}
}
return DRAW;
}
7.创建Game界面
void Game()
{
char board[ROW][COL];
InitBoard(board, ROW, COL);
srand((unsigned long)time(NULL));
char result = 0;
while (1){
ShowBoard(board, ROW, COL);
PlayerMove(board, ROW, COL);
result = IsEnd(board, ROW, COL);
if (result != NEXT){
break;
}
ShowBoard(board, ROW, COL);
ComputerMove(board, ROW, COL);
result = IsEnd(board, ROW, COL);
if (result != NEXT){
break;
}
}
ShowBoard(board, ROW, COL);
switch (result){
case WHITE:
printf("You win!\n");
break;
case BLACK:
printf("you lose!\n");
break;
case DRAW:
printf("it ends in a draw\n");
break;
defult:
printf("bug\n");
break;
}
}
完整代码
//main.c文件
#include"game.h"
void Meau(){
printf("+------ meau ----------+\n");
printf("|---- 1.play --------|\n");
printf("|---- 0.quit --------|\n");
printf("+----------------------+\n");
}
int main(){
int select = 0;
int quit = 0;
while (!quit)
{
Meau();
printf("please enter your choose: ");
scanf("%d", &select);
switch (select)
{
case 1:
Game();
break;
case 0:
quit = 1;
break;
defult:
printf("Select error!Try again!\n");
break;
}
}
printf("byebye!\n");
system("pause");
return 0;
}
//game.c 文件
#include"game.h"
static void InitBoard(char board[][COL], int row, int col){
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
board[i][j] = INIT;
}
}
}
static void ShowBoard(char board[][COL],int row,int col){
system("cls");
printf(" ");
for (int i = 0; i < col; i++){
printf(" %3d", i + 1);
}
printf("\n----------------\n");
for (int i = 0; i < row; i++){
printf("%-2d", i + 1);
for (int j = 0; j < col; j++){
printf("| %c ", board[i][j]);
}
printf("\n----------------\n");
}
}
static char IsEnd(char board[][COL], int row, int col){
for (int i = 0; i < row; i++){
if (board[i][0] == board[i][1] && \
board[i][1] == board[i][2] && \
board[i][0] != INIT){
return board[i][0];
}
}
for (int j = 0; j < col; j++){
if (board[0][j] == board[1][j] && \
board[1][j] == board[2][j] && \
board[0][j] != INIT){
return board[0][j];
}
}
if (board[0][0] == board[1][1] && \
board[1][1] == board[2][2] && \
board[0][0] != INIT){
return board[0][0];
}
if(board[0][2] == board[1][1] && \
board[1][1] == board[2][0] && \
board[1][1] != INIT){
return board[1][1];
}
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
if (board[i][j] == INIT);
return NEXT;
}
}
return DRAW;
}
static void PlayerMove(char board[][COL], int row, int col){
int x = 0;
int y = 0;
while (1){
printf("please enter your postion<x,y>: ");
scanf("%d %d", &x, &y);
if (x<1 || x>3 || y<1 || y>3){
printf("Postion Error!");
continue;
}
if (board[x - 1][y - 1] == INIT){
board[x - 1][y - 1] = WHITE;
break;
}
else{
printf("Postion Is Not Empty!\n");
}
}
}
static void ComputerMove(char board[][COL], int row, int col){
while (1){
int x = rand() % row;
int y = rand() % col;
if (board[x][y] == INIT){
board[x][y] = BLACK;
break;
}
}
}
void Game()
{
char board[ROW][COL];
InitBoard(board, ROW, COL);
srand((unsigned long)time(NULL));
char result = 0;
while (1){
ShowBoard(board, ROW, COL);
PlayerMove(board, ROW, COL);
result = IsEnd(board, ROW, COL);
if (result != NEXT){
break;
}
ShowBoard(board, ROW, COL);
ComputerMove(board, ROW, COL);
result = IsEnd(board, ROW, COL);
if (result != NEXT){
break;
}
}
ShowBoard(board, ROW, COL);
switch (result){
case WHITE:
printf("You win!\n");
break;
case BLACK:
printf("you lose!\n");
break;
case DRAW:
printf("it ends in a draw\n");
break;
defult:
printf("bug\n");
break;
}
}
//game.h文件
#ifndef __GAME_H__
#define __GAME_H__
#include<stdio.h>
#include <time.h>
#include <stdlib.h>
#include<windows.h>
#pragma warning(disable:4996)
#define ROW 3
#define COL 3
#define INIT ' '
#define WHITE 'X'//player
#define BLACK 'O'//computer
#define DRAW 'D'
#define NEXT 'N'
extern void Game();
#endif
代码结果显示
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。
以上是 用C语言实现三子棋 的全部内容, 来源链接: utcz.com/p/246220.html