React 在body上绑定事件以及阻止事件冒泡
<!DOCTYPE html><html>
<head>
<meta charset="UTF-8" />
<title>React 在body上绑定事件以及阻止事件冒泡</title>
<script src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<script src="https://unpkg.com/babel-standalone@6.15.0/babel.min.js"></script>
<style>
html{height: 100%;}
body{height: 100%;background-color: rgba(0,0,0,0.2);}
.m-outer{background-color: red;}
</style>
</head>
<body>
<div ></div>
<script type="text/babel">
class Toggle extends React.Component {
constructor(props) {
super(props);
this.state = {isToggleOn: true};
// 这个绑定是必要的,使`this`在回调中起作用
this.handleClick = this.handleClick.bind(this);
}
componentDidMount() {
document.body.addEventListener('click', e => {
if (e.target && e.target.matches('#m-btn')) {
return;
}
console.log('body');
});
}
componentWillUnmount() {
document.body.removeEventListener('click');
}
handleClick() {
this.setState(prevState => ({
isToggleOn: !prevState.isToggleOn
}));
}
render() {
return (
<button onClick={this.handleClick} >
{this.state.isToggleOn ? 'ON' : 'OFF'}
</button>
);
}
}
ReactDOM.render(
<Toggle />,
document.getElementById('root')
);
</script>
</body>
</html>
以上是 React 在body上绑定事件以及阻止事件冒泡 的全部内容, 来源链接: utcz.com/z/381350.html