Pandas中两个dataframe的交集和差集的示例代码

创建测试数据:

import pandas as pd

import numpy as np

#Create a DataFrame

df1 = {

'Subject':['semester1','semester2','semester3','semester4','semester1',

'semester2','semester3'],

'Score':[62,47,55,74,31,77,85]}

df2 = {

'Subject':['semester1','semester2','semester3','semester4'],

'Score':[90,47,85,74]}

df1 = pd.DataFrame(df1,columns=['Subject','Score'])

df2 = pd.DataFrame(df2,columns=['Subject','Score'])

print(df1)

print(df2)

运行结果:

求两个dataframe的交集

intersected_df = pd.merge(df1, df2, how='inner')

print(intersected_df)


也可以指定求交集的列:

intersected_df = pd.merge(df1, df2, on=['Subject'], how='inner')

print(intersected_df)

求差集

df2-df1:

set_diff_df = pd.concat([df2, df1, df1]).drop_duplicates(keep=False)

print(set_diff_df)

df1-df2:

set_diff_df = pd.concat([df1, df2, df2]).drop_duplicates(keep=False)

print(set_diff_df)


另一种求差集的方法是:

以df1-df2为例:

df1 = df1.append(df2)

df1 = df1.append(df2)

set_diff_df = df1.drop_duplicates(subset=['Subject', 'Score'],keep=False)

print(set_diff_df)

得到的df1-df2结果是一样的:

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