python计算两个矩形框重合百分比的实例

如下所示:

def mat_inter(box1,box2):

# 判断两个矩形是否相交

# box=(xA,yA,xB,yB)

x01, y01, x02, y02 = box1

x11, y11, x12, y12 = box2

lx = abs((x01 + x02) / 2 - (x11 + x12) / 2)

ly = abs((y01 + y02) / 2 - (y11 + y12) / 2)

sax = abs(x01 - x02)

sbx = abs(x11 - x12)

say = abs(y01 - y02)

sby = abs(y11 - y12)

if lx <= (sax + sbx) / 2 and ly <= (say + sby) / 2:

return True

else:

return False

def solve_coincide(box1,box2):

# box=(xA,yA,xB,yB)

# 计算两个矩形框的重合度

if mat_inter(box1,box2)==True:

x01, y01, x02, y02 = box1

x11, y11, x12, y12 = box2

col=min(x02,x12)-max(x01,x11)

row=min(y02,y12)-max(y01,y11)

intersection=col*row

area1=(x02-x01)*(y02-y01)

area2=(x12-x11)*(y12-y11)

coincide=intersection/(area1+area2-intersection)

return coincide

else:

return False

以上这篇python计算两个矩形框重合百分比的实例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持。

以上是 python计算两个矩形框重合百分比的实例 的全部内容, 来源链接: utcz.com/z/336541.html

回到顶部