在Elasticsearch中汇总值数组

  • Z时代
  • 2024-01-10
  • 分类：问答

我需要如下汇总一个数组

两个文档示例：

{
    "_index": "log",
    "_type": "travels",
    "_id": "tnQsGy4lS0K6uT3Hwzzo-g",
    "_score": 1,
    "_source": {
        "state": "saopaulo",
        "date": "2014-10-30T17",
        "traveler": "patrick",
        "registry": "123123",
        "cities": {
            "saopaulo": 1,
            "riodejaneiro": 2,
            "total": 2
        },
        "reasons": [
            "Entrega de encomenda"
        ],
        "from": [
            "CompraRapida"
        ]
    }
},
{
    "_index": "log",
    "_type": "travels",
    "_id": "tnQsGy4lS0K6uT3Hwzzo-g",
    "_score": 1,
    "_source": {
        "state": "saopaulo",
        "date": "2014-10-31T17",
        "traveler": "patrick",
        "registry": "123123",
        "cities": {
            "saopaulo": 1,
            "curitiba": 1,
            "total": 2
        },
        "reasons": [
            "Entrega de encomenda"
        ],
        "from": [
            "CompraRapida"
        ]
    }
},

我想聚集cities阵列，找出所有cities的traveler已经去了。我想要这样的东西：

{
    "traveler":{
        "name":"patrick"
    },
    "cities":{
        "saopaulo":2,
        "riodejaneiro":2,
        "curitiba":1,
        "total":3
    }
}

其中，total是cities数组长度减去1 的长度。我尝试了术语“聚合”和“和”，但无法输出所需的输出。

可以对文档结构进行更改，因此，如果这样对我有所帮助，我将很高兴知道。

回答：

在“ ” 上方发布的文档中，它不是json数组，而是json对象。如果可以更改文档结构，则可以将文档中的城市更改为对象数组

 cities : [
   {
     "name" :"saopaulo"
     "visit_count" :"2",
   },
   {
     "name" :"riodejaneiro"
     "visit_count" :"1",
   }
]

然后，您需要将城市设置为嵌套在索引映射中的类型

   "mappings": {
         "<type_name>": {
            "properties": {
               "cities": {
                  "type": "nested",
                  "properties": {
                     "city": {
                        "type": "string"
                     },
                     "count": {
                        "type": "integer"
                     },
                     "value": {
                        "type": "long"
                     }
                  }
               },
               "date": {
                  "type": "date",
                  "format": "dateOptionalTime"
               },
               "registry": {
                  "type": "string"
               },
               "state": {
                  "type": "string"
               },
               "traveler": {
                  "type": "string"
               }
            }
         }
      }

之后，您可以使用嵌套聚合来获取每个用户的城市计数。查询将在以下几行中显示：

{
   "query": {
      "match": {
         "traveler": "patrick"
      }
   },
   "aggregations": {
      "city_travelled": {
         "nested": {
            "path": "cities"
         },
         "aggs": {
            "citycount": {
               "cardinality": {
                  "field": "cities.city"
               }
            }
         }
      }
   }
}

以上是 在Elasticsearch中汇总值数组 的全部内容， 来源链接： utcz.com/qa/415163.html

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