Ajax jQuery同步回调成功

  • Z时代
  • 2024-01-10
  • 分类：问答

我有这个功能，使一个ajax调用。我在最后一段代码注释中描述了问题。

    function doop(){
            var that = this;
            var theold = "theold";
            var thenew = "thenew";
            $.ajax({
                    url: 'doop.php',
                    type: 'POST',
                    data: 'before=' + theold + '&after=' + thenew,
                    success: function(resp) {
                            if(resp == 1) {
                                    $(that).siblings('.theold').html(thenew);
                            }
                    }
            });
            // I have some code here (out of the ajax) that **further** changes 
            // the .theold's html beyond what it was changed inside ajax success
            // but the change depends on whether the resp (inside the success 
            // function) returned 1 or not, so this code out here depends on the ajax
            // so it looks like I have to turn this ajax call into a sync ajax
            return false;
    }

根据代码注释中描述的问题，哪种更改最适合这种情况？

回答：

您需要为以下同步请求设置async：false：

function doop(){
        var that = this;
        var theold = $(this).siblings('.theold').html();
        var thenew = $(this).siblings('.thenew').val();
        $.ajax({
                async: false,
                url: 'doop.php',
                type: 'POST',
                data: 'before=' + theold + '&after=' + thenew,
                success: function(resp) {
                        if(resp == 1) {
                                $(that).siblings('.theold').html(thenew);
                        }
                }
        });
        // some other code
        return false;
}

详情请看这里

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