java.sql.SQLExceptionColumnindexoutofrange. [数据库教程]
public <E> List<E> selectList(Mapper mapper, Connection conn){
PreparedStatement pstm = null;
ResultSet rs = null;
try{
String queryString = mapper.getQueryString();
String resultType = mapper.getResultType();
Class domainClass = Class.forName(resultType);
pstm = conn.prepareStatement(queryString);
rs = pstm.executeQuery();
List<E> list = new ArrayList<E>();
while(rs.next()){
E obj = (E)domainClass.newInstance();
ResultSetMetaData rsmd = rs.getMetaData();
int columnCount = rsmd.getColumnCount();
System.out.println(columnCount);
for(int i =0 ;i<=columnCount;i++){
//获取每列的名
String columnName = rsmd.getColumnName(i);
//获取每列值
Object columnValue = rs.getObject(columnName);
//给obj赋值,使用的是java内省机制(借助PropertyDescriptor实现属性的封装)
PropertyDescriptor pd = new PropertyDescriptor(columnName,domainClass);
Method writeMethod = pd.getWriteMethod();
writeMethod.invoke(obj,columnValue);
}
list.add(obj);
}
return list;
}catch (Exception e){
throw new RuntimeException(e);
}
}
这样会报错
java.sql.SQLException: Column index out of range.
解决办法
java.sql.SQLException: Column index out of range.
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