oracle查询两个字段值相同的记录

  • Z时代
  • 2024-01-10
  • 分类：综合

database

select A.* from tb_mend_enrol A,
                (select A.Typeid, A.address from tb_mend_enrol A
                  group by A.Typeid, A.address
                  having count(A.Typeid) >= 2 and count(A.address) >= 2 ) B
where A.Typeid = B.Typeid  and A.address = B.address and a.reporter="测试" 
and  A.reptime >= to_date("2018-08-01 00:00:00","YYYY-MM-DD HH24:MI:SS")
order by A.Address, A.reptime 


方法二：

select A.* from tb_mend_enrol A
where (select count(*) from tb_mend_enrol A1
where A1.Typeid = A.Typeid and A1.address=A.address)>1
and a.reporter="测试"
and A.reptime >= to_date("2018-08-01 00:00:00","YYYY-MM-DD HH24:MI:SS"
order by A.Address

　　

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