python实现mask矩阵示例(根据列表所给元素)

行和列的位置都在以下三个列表中的一列中,则对应位置为1,其余位置全为0

​ ——[7-56,239-327,438-454,522-556,574-586]

​ ——[57-85,96-112,221-238]

​ ——[113-220,328-437,455-521,557-573]

代码实现

def generateMaskBasedOnDom(dom_path, length):

"""

:param dom_path: this is a file path, which contains the following information:

[7-56,239-327,438-454,522-556,574-586][57-85,96-112,221-238][113-220,328-437,455-521,557-573]

each [...] means one domain

:param length: this is the length of this protein

:return: the mask matrix with size length x length, 1 means inner domain residue pair, otherwise 0

"""

# 读取文件

with open(dom_path, "r", encoding="utf-8") as file:

contents = file.readlines()

# 获得mask位置数据

list0 = []

list1 = []

list2 = []

for list_idx, content in enumerate(contents):

num_range_list = content.strip()[1:-1].split(",")

for num_range in num_range_list:

start_num = int(num_range.split("-")[0])

end_num = int(num_range.split("-")[1])

for num in range(start_num, end_num+1):

if list_idx == 0:

list0.append(num)

elif list_idx == 1:

list1.append(num)

else:

list2.append(num)

mask = np.zeros((length, length))

# 遍历矩阵每个元素

for row in range(mask.shape[0]):

for col in range(mask.shape[1]):

if (row in list0 and col in list0) or (row in list1 and col in list1) or (row in list2 and col in list2):

mask[row][col] = 1

return mask

if __name__ == "__main__":

# if no dom file ,please get dom file first

with open("dom.txt", "w", encoding="utf-8") as f:

f.write("[7-56,239-327,438-454,522-556,574-586]" + "\n" + "[57-85,96-112,221-238]" + "\n" + "[113-220,328-437,455-521,557-573]")

file_path = "./dom.txt"

protein_length = 1000 # mask_matrix size

mask_matrix = generateMaskBasedOnDom(file_path, protein_length)

print("*************Generate Mask Matrix Successful!*************")

# 随机测试几组

print(mask_matrix[7][56]) # 1

print(mask_matrix[7][239]) # 1

print(mask_matrix[8][57]) # 0

print(mask_matrix[57][95]) # 0

print(mask_matrix[113][573]) # 1

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