php+ajax+json 详解及实例代码

php+ajax+json 实例代码

html页面:

<html>

<head>

<meta http-equiv="content-type" content="text/html;charset=utf-8" />

<script type="text/javascript" src="jquery-1.8.2.min.js"></script>

<script type="text/javascript">

$(function(){

$("#send").click(function(){

var cont = $("input").serialize();

$.ajax({

url:'ab.php',

type:'post',

dataType:'json',

data:cont,

success:function(data){

var str = data.username + data.age + data.job;

$("#result").html(str);

}

});

});

});

</script>

</head>

<body>

<div id="result">一会看显示结果</div>

<form id="my" action="" method="post">

<p><span>姓名:</span> <input type="text" name="username" /></p>

<p><span>年龄:</span><input type="text" name="age" /></p>

<p><span>工作:</span><input type="text" name="job" /></p>

</form>

<button id="send">提交</button>

</body>

</html>

 php页面:

<?php

header("Content-type:text/html;charset=utf-8");

$username = $_POST['username'];

$age = $_POST['age'];

$job = $_POST['job'];

$json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);

$json_obj = json_encode($json_arr);

echo $json_obj;

?>

使用post方式

<script type="text/javascript">

$(function(){

$("#send").click(function(){

var cont = {username:$("input")[0].value,age:$("input")[1].value,job:$("input")[2].value};

var url = 'ab.php';

$.post(url,cont,function(data){

var res = eval("(" + data + ")");//转为Object对象

var str = res.username + res.age + res.job;

$("#result").html(str);

});

});

});

</script>

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