C语言实现2048游戏
本文实例为大家分享了C语言实现2048小游戏的具体代码，供大家参考，具体内容如下
具有以下特点：
1.linux下完成
2.非堵塞键盘读取
3.随机生成2和4
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#define TTY_PATH "/dev/tty"
#define STTY_ON "stty raw -echo -F"
#define STTY_OFF "stty -raw echo -F"
int map[4][4];
typedef struct node
{
int x;
int y;
int num;
}Node;
Node node;
void init_map()//初始化全部方格
{
int i, j;
for(i=0; i<4; i++)
for(j=0; j<4; j++)
map[i][j] = 0;
}
void new_node()//新增方格，避免重复。
{
int x = 0, y = 0 ,num = 0;
do{
int fals = 1;
int i,j;
for(i=0; i<4; i++)
for(j=0; j<4; j++)
if(map[i][j] == 0)
fals =0;
if(fals)//新方格无法被填入，游戏失败
{
system("clear");
printf("game over!!!!!!!!!!!\n");
exit(0);
}
x = rand() % 4;
y = rand() % 4;
num = rand() % 2;
if(num == 0)
num = 3;
else if(num == 1)
num = 5;
}while(map[x][y] > 0);
node.x = x;
node.y = y;
node.num = num;
map[x][y] = node.num;
}
void show()//彩色打印数字
{
int i, j;
for(i=0; i<4; i++)
{
for(j=0; j<4; j++)
{
if(map[i][j]%2 == 1)
{
map[i][j] -= 1;
printf("\33[31m%d\33[0m\t",map[i][j]);
}
else if(map[i][j] == 0)
{
printf("%d\t",map[i][j]);
}
else if(map[i][j] == 2)
{
printf("\33[32m%d\33[0m\t",map[i][j]);
}
else if(map[i][j] == 4)
{
printf("\33[33m%d\33[0m\t",map[i][j]);
}
else if(map[i][j] == 8)
{
printf("\33[34m%d\33[0m\t",map[i][j]);
}
else if(map[i][j] == 16)
{
printf("\33[35m%d\33[0m\t",map[i][j]);
}
else if(map[i][j] == 32)
{
printf("\33[36m%d\33[0m\t",map[i][j]);
}
else
{
printf("\33[44m%d\33[0m\t",map[i][j]);
}
}
printf("\n");
}
}
void left()
{
int i, j, z, tmp;
for(i=0; i<4; i++)//全体方格左移
for(j=0; j<4; j++)
if(map[i][j] == 0 )
for(z = j + 1; z<4; z++)
if(map[i][z] > 0)
{
tmp = map[i][j];
map[i][j] = map[i][z];
map[i][z] = tmp;
break;
}
for(i=0; i<4; i++)//如果方格数字相同则，相加，通过主函数多次调用，排列好
for(j=0; j<4; j++)
if(map[i][j] > 0 )
for(z = j + 1; z<4; z++)
if(map[i][z] > 0)
if(map[i][z] == map[i][j])
{
map[i][j] *= 2;
map[i][z] = 0;
}else
break;
else
break;
else
break;
}
void right()
{
int i, j, z, tmp;
for(i=0; i<4; i++)
for(j=3; j>=0; j--)
if(map[i][j] == 0 )
for(z = j-1; z>=0; z--)
if(map[i][z] > 0)
{
tmp = map[i][j];
map[i][j] = map[i][z];
map[i][z] = tmp;
break;
}
for(i=0; i<4; i++)
for(j=3; j>=0; j--)
if(map[i][j] > 0 )
for(z = j-1; z>=0; z--)
if(map[i][z] > 0)
if(map[i][z] == map[i][j])
{
map[i][j] *= 2;
map[i][z] = 0;
}else
break;
else
break;
else
break;
}
void up()
{
int i, j, z, tmp;
for(i=0; i<4; i++)
for(j=0; j<4; j++)
if(map[j][i] == 0 )
for(z = j+1; z<4; z++)
if(map[z][i] > 0)
{
tmp = map[j][i];
map[j][i] = map[z][i];
map[z][i] = tmp;
break;
}
for(i=0; i<4; i++)
for(j=0; j<4; j++)
if(map[j][i] > 0 )
for(z = j+1; z<4; z++)
if(map[z][i] > 0)
if(map[z][i] == map[j][i])
{
map[j][i] *= 2;
map[z][i] = 0;
}else
break;
else
break;
else
break;
}
void down()
{
int i, j, z, tmp;
for(i=0; i<4; i++)
for(j=3; j>=0; j--)
if(map[j][i] == 0 )
for(z = j-1; z>=0; z--)
if(map[z][i] > 0)
{
tmp = map[j][i];
map[j][i] = map[z][i];
map[z][i] = tmp;
break;
}
for(i=0; i<4; i++)
for(j=3; j>=0; j--)
if(map[j][i] > 0 )
for(z = j-1; z>=0; z--)
if(map[z][i] > 0)
if(map[z][i] == map[j][i])
{
map[j][i] *= 2;
map[z][i] = 0;
}else
break;
else
break;
else
break;
}
void move(char ch)
{
switch(ch)
{
case 'a':
left();
break;
case 'd':
right();
break;
case 'w':
up();
break;
case 's':
down();
break;
}
}
char in_direct()//非堵塞输入
{
fd_set fd;
struct timeval tv;
char ch;
FD_ZERO(&fd);
FD_SET(0, &fd);
tv.tv_sec = 0;
tv.tv_usec = 10;
if(select(1, &fd ,NULL, NULL, &tv) > 0)
{
ch = getchar();
}
return ch;
}
int main()
{
srand(time(NULL));
init_map();
new_node();
show();
char ch;
int i=0;
while(1)
{
system(STTY_ON TTY_PATH);
ch = in_direct();
system(STTY_OFF TTY_PATH);
if(ch=='a'||ch=='d'||ch=='s'||ch=='w')
{
system("clear");
for(i=0;i<3;i++)//重复多次才能排序好
move(ch);
new_node();
show();
}
if(ch=='q')//退出游戏
{
system("clear");
printf("game over!!!!!!!!\n");
break;
}
usleep(500000);
}
return 0;
}
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