c++实现对输入数组进行快速排序的示例(推荐)

废话不多说,直接上代码

#include "stdafx.h"

#include <iostream>

#include <string>

#include <vector>

using namespace std;

void quickSort(vector<int> &a, int, int);

void swap(int &a, int&b);

vector<string> split(string s, string seperator);

int main() {

string str;

cout << "please input your array: " << endl;

getline(cin, str);

vector<string> strs = split(str, " ");

cout << "The original array is " << endl;

for (unsigned int i = 0; i < strs.size(); i++) {

cout << strs[i] << " ";

}

cout << endl;

vector<int> array(strs.size());

for (unsigned int i = 0; i < strs.size(); i++) {

array[i] = atoi(strs[i].c_str());

}

int len = array.size();

cout << "The ordered array is " << endl;

quickSort(array, 0, len-1);

for (int i = 0; i < len; i++) {

cout << array[i] << " ";

}

cout << endl;

system("pause");

return 0;

}

void quickSort(vector<int> &a, int start, int base) {

if (start >= base) {

return;

}

int i = start, j = start;

int temp = a[base];

for (;j<base;j++) {

if (a[j]<=temp) {

swap(a[i], a[j]);

i++;

}

}

if (a[i] > a[base]) {

swap(a[i], a[base]);

}

quickSort(a, start, i - 1);

quickSort(a, i + 1, base);

}

void swap(int &a, int&b) {

if (a == b) {

}

else {

a = a + b;

b = a - b;

a = a - b;

}

}

vector<string> split(string s, const string pattern) {

string::size_type pos;

vector<string> result;

s += pattern;

unsigned int size = s.size();

for (unsigned int i = 0; i < size; i++) {

pos = s.find(pattern, i);

if (pos < size) {

string str = s.substr(i, pos - i);

if (!str.empty()){

result.push_back(str);

}

i = pos + pattern.size() - 1;

}

}

return result;

}

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