c++实现对输入数组进行快速排序的示例(推荐)
废话不多说,直接上代码
#include "stdafx.h"
#include <iostream>
#include <string>
#include <vector>
using namespace std;
void quickSort(vector<int> &a, int, int);
void swap(int &a, int&b);
vector<string> split(string s, string seperator);
int main() {
string str;
cout << "please input your array: " << endl;
getline(cin, str);
vector<string> strs = split(str, " ");
cout << "The original array is " << endl;
for (unsigned int i = 0; i < strs.size(); i++) {
cout << strs[i] << " ";
}
cout << endl;
vector<int> array(strs.size());
for (unsigned int i = 0; i < strs.size(); i++) {
array[i] = atoi(strs[i].c_str());
}
int len = array.size();
cout << "The ordered array is " << endl;
quickSort(array, 0, len-1);
for (int i = 0; i < len; i++) {
cout << array[i] << " ";
}
cout << endl;
system("pause");
return 0;
}
void quickSort(vector<int> &a, int start, int base) {
if (start >= base) {
return;
}
int i = start, j = start;
int temp = a[base];
for (;j<base;j++) {
if (a[j]<=temp) {
swap(a[i], a[j]);
i++;
}
}
if (a[i] > a[base]) {
swap(a[i], a[base]);
}
quickSort(a, start, i - 1);
quickSort(a, i + 1, base);
}
void swap(int &a, int&b) {
if (a == b) {
}
else {
a = a + b;
b = a - b;
a = a - b;
}
}
vector<string> split(string s, const string pattern) {
string::size_type pos;
vector<string> result;
s += pattern;
unsigned int size = s.size();
for (unsigned int i = 0; i < size; i++) {
pos = s.find(pattern, i);
if (pos < size) {
string str = s.substr(i, pos - i);
if (!str.empty()){
result.push_back(str);
}
i = pos + pattern.size() - 1;
}
}
return result;
}
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