Python-如何在Flask中提供静态文件

我有一个应用程序,该应用程序已集成在一起,Flask现在它只提供一个静态HTML页面,其中包含指向CSS和JS的链接。而且我找不到文档中Flask描述返回静态文件的位置。是的,我可以使用,render_template但是我知道数据没有模板化。我还以为send_file或者url_for是正确的事情,但我不能让这些工作。同时,我正在打开文件,阅读内容,并装配Response具有适当mimetype的:

import os.path

from flask import Flask, Response

app = Flask(__name__)

app.config.from_object(__name__)

def root_dir(): # pragma: no cover

return os.path.abspath(os.path.dirname(__file__))

def get_file(filename): # pragma: no cover

try:

src = os.path.join(root_dir(), filename)

# Figure out how flask returns static files

# Tried:

# - render_template

# - send_file

# This should not be so non-obvious

return open(src).read()

except IOError as exc:

return str(exc)

@app.route('/', methods=['GET'])

def metrics(): # pragma: no cover

content = get_file('jenkins_analytics.html')

return Response(content, mimetype="text/html")

@app.route('/', defaults={'path': ''})

@app.route('/<path:path>')

def get_resource(path): # pragma: no cover

mimetypes = {

".css": "text/css",

".html": "text/html",

".js": "application/javascript",

}

complete_path = os.path.join(root_dir(), path)

ext = os.path.splitext(path)[1]

mimetype = mimetypes.get(ext, "text/html")

content = get_file(complete_path)

return Response(content, mimetype=mimetype)

if __name__ == '__main__': # pragma: no cover

app.run(port=80)

有人要为此提供代码示例或网址吗?我知道这将变得简单。

回答:

首选方法是使用nginx或其他Web服务器提供静态文件。他们将比Flask更有效率。

但是,你可以用来send_from_directory从目录发送文件,这在某些情况下非常方便:

from flask import Flask, request, send_from_directory

# set the project root directory as the static folder, you can set others.

app = Flask(__name__, static_url_path='')

@app.route('/js/<path:path>')

def send_js(path):

return send_from_directory('js', path)

if __name__ == "__main__":

app.run()

千万不能使用send_file或send_static_file与用户提供的路径。

send_static_file 例:

from flask import Flask, request

# set the project root directory as the static folder, you can set others.

app = Flask(__name__, static_url_path='')

@app.route('/')

def root():

return app.send_static_file('index.html')

以上是 Python-如何在Flask中提供静态文件 的全部内容, 来源链接: utcz.com/qa/433186.html

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