将Soap XML响应转换为对象

  • Z时代
  • 2024-01-10
  • 分类：问答

我是使用SOAP API的新手

我有一个来自API的肥皂响应

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<LoginResponse xmlns="http://test.org/ADMail_Service">
<LoginResult>
<ErrorMessage>Successful login</ErrorMessage>
<Status>true</Status>
</LoginResult>
</LoginResponse>
</soapenv:Body>
</soapenv:Envelope>

我正在尝试将其转换为对象。

通过在线阅读文章，我试图使用JAXB来做到这一点，但是我的对象是空的。

这是读取响应的代码。我将响应写到xml文件中以进行测试：

try {
    XMLInputFactory xif = XMLInputFactory.newFactory();
    XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
    xsr.nextTag(); // Advance to Envelope tag
    xsr.nextTag(); // Advance to Body tag
    xsr.nextTag();
    xsr.nextTag();
    JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
    Unmarshaller unmarshaller = jc.createUnmarshaller();
    JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);
    System.out.println(je.getName());
    System.out.println(je.getValue());
} catch (XMLStreamException e) {
    e.printStackTrace();
} catch (JAXBException e) {
    e.printStackTrace();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}

本LoginResult类：

public class LoginResult {
    private String errorMessage;
    private String status;
    public String getErrorMessage() {
        return errorMessage;
    }
    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }
    public String getStatus() {
        return status;
    }
    public void setStatus(String status) {
        this.status = status;
    }
}

提前致谢！

回答：

您可以使用此代码检索POJO，还可以将@XmlRootElement作为标头添加到POJO。

（我没有测试下面的代码）

XMLInputFactory xif = XMLInputFactory.newFactory();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
        xsr.nextTag(); // Advance to Envelope tag
        xsr.nextTag(); // Advance to Body tag
        xsr.nextTag();
        xsr.nextTag();
        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StringWriter stringWriter = new StringWriter();
        transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
        StringReader sr = new StringReader(stringWriter.toString());
        JAXBContext jaxbContext = JAXBContext.newInstance(LoginResult.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        LoginResult loginResult = (LoginResult) unmarshaller.unmarshal(sr);

我为您找到了解决方案：

    @XmlRootElement(name = "LoginResult", namespace = "http://test.org/ADMail_Service")
@XmlAccessorType(XmlAccessType.FIELD)
public class LoginResult {
    @XmlElement(name = "ErrorMessage", namespace = "http://test.org/ADMail_Service")
    private String errorMessage;
    @XmlElement(name = "Status", namespace = "http://test.org/ADMail_Service")
    private String status;
    public String getErrorMessage() {
        return errorMessage;
    }
    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }
    public String getStatus() {
        return status;
    }
    public void setStatus(String status) {
        this.status = status;
    }
}
public static void main(String[] args) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
            xsr.nextTag(); // Advance to Envelope tag
            xsr.nextTag(); // Advance to Body tag
            xsr.nextTag();
            xsr.nextTag();
            JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
            Unmarshaller unmarshaller = jc.createUnmarshaller();
            JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);
            System.out.println(je.getName());
            System.out.println(je.getValue());
            System.out.println(je.getValue().getErrorMessage());
        } catch (XMLStreamException e) {
            e.printStackTrace();
        } catch (JAXBException e) {
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }
    }

以上是 将Soap XML响应转换为对象 的全部内容， 来源链接： utcz.com/qa/429133.html

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