Go中的Os Exec Sudo命令
在熟悉Go和goroutine的过程中,我遇到了执行命令的障碍。这些命令的格式为:
sudo find /folder -type f | while read i; do sudo -S chmod 644 "$i"; done
使用从如何在Golang中执行系统命令的代码中获取未知参数的代码,我试图执行此命令,但是我相信由于第一个参数为sudo,该命令未执行,这可能是错误的。我只有两个问题。
当这些命令无法运行时,我将返回“退出状态1”,是否有办法比我正在执行的操作得到更详细的错误?问题二,为什么我使用此脚本会获得“退出状态1”?那到底是怎么回事?
package mainimport (
"bufio"
"fmt"
"os"
"os/exec"
"strings"
"sync"
)
func ExeCmd(cmd string, wg *sync.WaitGroup) {
parts := strings.Fields(cmd)
head := parts[0]
// Head at this point is "sudo"
parts = parts[1:len(parts)]
out, err := exec.Command(head,parts...).Output()
if err != nil {
fmt.Printf("%s\n", err)
}
fmt.Printf("%s\n", out)
wg.Done() // Signal to WaitGroup goroutine finished
}
func InArray(a []string, e string) bool {
for _, x := range a {
if x == e {
return true
fmt.Print("True")
}
}
return false
}
func main() {
exec.Command("sudo ls > /dev/null") // Get sudo password just once, doesn't seem to work with Go
wg := new(sync.WaitGroup)
reader := bufio.NewReader(os.Stdin)
fdbslices := []string{"f", "d", "b", "files", "directories", "both"}
commands := []string{}
fdb := ""
filep := ""
dirp := ""
// Grab Path
fmt.Print("Path: ")
findpath, _ := reader.ReadString('\n')
findpath = strings.ToLower(strings.Trim(findpath, "\n"))
// Grab Files, Directories, or Both
for {
fmt.Print("Files, Directories, or Both: ")
fdb, _ = reader.ReadString('\n')
fdb = strings.ToLower(strings.Trim(fdb, "\n"))
if InArray(fdbslices, fdb) == true { break }
}
// Build commands string, these come out as they should
for {
if fdb == "f" || fdb == "files" {
fmt.Print("Permissions for Files: ")
filep, _ = reader.ReadString('\n')
filep = strings.Trim(filep, "\n")
commands = append(commands, "sudo find " + findpath + " -type f | while read i; do sudo -S chmod " + filep + " \"$i\"; done")
}
if fdb == "d" || fdb == "directories" {
fmt.Print("Permissions for Directories: ")
dirp, _ = reader.ReadString('\n')
dirp = strings.Trim(dirp, "\n")
commands = append(commands, "sudo find " + findpath + " -type d | while read i; do sudo -S chmod " + dirp + " \"$i\"; done")
}
if fdb == "b" || fdb == "both" {
fmt.Print("Permissions for Files: ")
filep, _ = reader.ReadString('\n')
filep = strings.Trim(filep, "\n")
commands = append(commands, "sudo find " + findpath + " -type f | while read i; do sudo -S chmod " + filep + " \"$i\"; done")
fmt.Print("Permissions for Directories: ")
dirp, _ = reader.ReadString('\n')
dirp = strings.Trim(dirp, "\n")
commands = append(commands, "sudo find " + findpath + " -type d | while read i; do sudo -S chmod " + dirp + " \"$i\"; done")
}
break
}
// Execute Commands
for _, str := range commands {
wg.Add(1)
fmt.Print("Doing: " + str + "\r\n")
go ExeCmd(str, wg)
}
wg.Wait()
}
终端输出示例:
Path: testFiles, Directories, or Both: b
Permissions for Files: 644
Permissions for Directories: 755
Doing: find test -type f | while read i; do sudo -S chmod 644 "$i"; done
Doing: find test -type d | while read i; do sudo -S chmod 755 "$i"; done
exit status 1
exit status 1
感谢您的时间。
回答:
exec.Command()
将要求内核直接执行给定的进程。但是,您传递的命令是由外壳程序脚本链接在一起的多个程序的字符串。
如果要执行Shell脚本,则应使用以下内容:
cmd := exec.Command("/bin/sh", "-c", "sudo find ...")
以上是 Go中的Os Exec Sudo命令 的全部内容, 来源链接: utcz.com/qa/428893.html