Python-Flask视图引发TypeError：“ bool”对象不可调用

  • Z时代
  • 2024-01-10
  • 分类：问答

我试图调试我的Flask应用程序中的视图，该视图返回500状态，并TypeError: 'bool' object is not callable在追溯中出现错误。然后login_user从Flask-Login进行的视图调用返回True以指示登录成功。

我进行了调试，直到app_iter = app(environ, start_response)，app现在是具有值True而不是Flask应用程序对象的布尔值。

Traceback (most recent call last):
  File "D:\Python27\lib\site-packages\flask\app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "D:\Python27\lib\site-packages\flask\app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "D:\Python27\lib\site-packages\flask\app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "D:\Python27\lib\site-packages\flask\app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "D:\Python27\lib\site-packages\flask\app.py", line 1478, in full_dispatch_request
    response = self.make_response(rv)
  File "D:\Python27\lib\site-packages\flask\app.py", line 1577, in make_response
    rv = self.response_class.force_type(rv, request.environ)
  File "D:\Python27\lib\site-packages\werkzeug\wrappers.py", line 824, in force_type
    response = BaseResponse(*_run_wsgi_app(response, environ))
  File "D:\Python27\lib\site-packages\werkzeug\wrappers.py", line 57, in _run_wsgi_app
    return _run_wsgi_app(*args)
  File "D:\Python27\lib\site-packages\werkzeug\test.py", line 854, in run_wsgi_app
    app_iter = app(environ, start_response)
TypeError: 'bool' object is not callable

@app.route('/login', methods=['POST'])
def login():
    username = request.form['username']
    user = User.query.filter_by(username=username).first()
    if user:
        login_user(user)
        return True
    return False

回答：

在Flask中，视图必须返回以下之一：

  • a string

  • a Response object (or subclass)

  • a tuple of (string, status, headers) or (string, status)

  • a valid WSGI application

前三个选项的Flask测试，如果不合适，则假定为第四个。你在某个地方返回了True，它将被视为WSGI应用程序。

请参阅文档中的关于响应。

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