如何读取JSch命令输出?
我有以下代码:
JSch jsch = new JSch();jsch.setKnownHosts(dotSshDir + "/known_hosts");
jsch.addIdentity(dotSshDir + "/id_rsa");
Session session = jsch.getSession(userName, hostname, 22);
session.connect();
ChannelExec channel = (ChannelExec) session.openChannel("exec");
channel.setCommand(command);
channel.setInputStream(null);
channel.setErrStream(System.err);
Reader reader = new InputStreamReader(channel.getInputStream());
char[] buf = new char[1024];
int numRead;
while ((numRead = reader.read(buf)) != -1) {
String readData = String.valueOf(buf, 0, numRead);
result.append(readData);
buf = new char[1024];
}
试图从阅读器中读取内容已挂起。我该如何解决?我该如何寻找正在发生的事情?
回答:
在等待命令完成的同时,必须连续读取输出。否则,如果命令产生足够的输出以填充输出缓冲区,则该命令将挂起,等待缓冲区被消耗,这将永远不会发生。这样您就陷入僵局。
以下示例在监视命令状态的同时连续读取stdout和stderr。它基于官方的JSch
exec.java
示例(仅添加了stderr的阅读)。
ChannelExec channel = (ChannelExec)session.openChannel("exec");channel.setCommand(
"for((i=1;i<=10000;i+=2)); do echo \"Long output - $i\"; done ; " +
"echo error output >&2");
InputStream commandOutput = channel.getExtInputStream();
StringBuilder outputBuffer = new StringBuilder();
StringBuilder errorBuffer = new StringBuilder();
InputStream in = channel.getInputStream();
InputStream err = channel.getExtInputStream();
channel.connect();
byte[] tmp = new byte[1024];
while (true) {
while (in.available() > 0) {
int i = in.read(tmp, 0, 1024);
if (i < 0) break;
outputBuffer.append(new String(tmp, 0, i));
}
while (err.available() > 0) {
int i = err.read(tmp, 0, 1024);
if (i < 0) break;
errorBuffer.append(new String(tmp, 0, i));
}
if (channel.isClosed()) {
if ((in.available() > 0) || (err.available() > 0)) continue;
System.out.println("exit-status: " + channel.getExitStatus());
break;
}
try {
Thread.sleep(1000);
} catch (Exception ee) {
}
}
System.out.println("output: " + outputBuffer.toString());
System.out.println("error: " + errorBuffer.toString());
channel.disconnect();
如果在while (!channel.isClosed()) {}
之后添加channel.connect();
,您会看到i
shell
for
循环中有足够大的空间(在我的环境中,10000就足够了),循环永远不会结束。
以上是 如何读取JSch命令输出? 的全部内容, 来源链接: utcz.com/qa/423978.html