Ajax处理中的“无效的JSON原语”

  • Z时代
  • 2024-01-10
  • 分类：问答

我在jQuery的ajax调用中遇到错误。

这是我的jQuery函数：

function DeleteItem(RecordId, UId, XmlName, ItemType, UserProfileId) {
    var obj = {
        RecordId: RecordId,
        UserId: UId,
        UserProfileId: UserProfileId,
        ItemType: ItemType,
        FileName: XmlName
    };
    var json = Sys.Serialization.JavaScriptSerializer.serialize(obj);
    $.ajax({
        type: "POST",
        url: "EditUserProfile.aspx/DeleteRecord",
        data: json,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        async: true,
        cache: false,
        success: function(msg) {
            if (msg.d != null) {
                RefreshData(ItemType, msg.d);
            }
        },
        error: function(XMLHttpRequest, textStatus, errorThrown) {
            alert("error occured during deleting");
        }
    });
}

这是我的WebMethod：

[WebMethod]
public static string DeleteRecord(Int64 RecordId, Int64 UserId, Int64 UserProfileId, string ItemType, string FileName) {
    try {
        string FilePath = HttpContext.Current.Server.MapPath(FileName);
        XDocument xmldoc = XDocument.Load(FilePath);
        XElement Xelm = xmldoc.Element("UserProfile");
        XElement parentElement = Xelm.XPathSelectElement(ItemType + "/Fields");
        (from BO in parentElement.Descendants("Record")
         where BO.Element("Id").Attribute("value").Value == RecordId.ToString()
         select BO).Remove();
        XDocument xdoc = XDocument.Parse(Xelm.ToString(), LoadOptions.PreserveWhitespace);
        xdoc.Save(FilePath);
        UserInfoHandler obj = new UserInfoHandler();
        return obj.GetHTML(UserId, UserProfileId, FileName, ItemType, RecordId, Xelm).ToString();
    } catch (Exception ex) {
        HandleException.LogError(ex, "EditUserProfile.aspx", "DeleteRecord");
    }
    return "success";
}

有人可以告诉我我的代码有什么问题吗？

我收到此错误：

{
    "Message":"Invalid JSON primitive: RecordId.",
    "StackTrace":"
       at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializePrimitiveObject()
       at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializeInternal(Int32 depth)
       at System.Web.Script.Serialization.JavaScriptObjectDeserializer.BasicDeserialize(String input, Int32 depthLimit, JavaScriptSerializer serializer)
       at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize(JavaScriptSerializer serializer, String input, Type type, Int32 depthLimit)
       at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize[T](String input)
       at System.Web.Script.Services.RestHandler.GetRawParamsFromPostRequest(HttpContext context, JavaScriptSerializer serializer)
       at System.Web.Script.Services.RestHandler.GetRawParams(WebServiceMethodData methodData, HttpContext context)
       at System.Web.Script.Services.RestHandler.ExecuteWebServiceCall(HttpContext context, WebServiceMethodData methodData)",
    "ExceptionType":"System.ArgumentException"
}

回答：

只是猜测变量json之后包含什么

var json = Sys.Serialization.JavaScriptSerializer.serialize(obj);?

如果它是一个有效的json对象，{'foo':'foovalue',

'bar':'barvalue'}那么jQuery可能不会将其作为json数据发送，而是将其序列化为，foor=foovalue&bar=barvalue因此您会收到错误消息"Invalid

JSON primitive: foo"

尝试改为将数据设置为字符串

$.ajax({
    ...
    data: "{'foo':'foovalue', 'bar':'barvalue'}", //note the additional quotation marks
    ...
})

这样，jQuery应该不理会数据并将字符串原样发送到服务器，这应允许ASP.NET解析json服务器端。

以上是 Ajax处理中的“无效的JSON原语” 的全部内容， 来源链接： utcz.com/qa/408485.html

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