杰克逊将即时序列化为纳秒级问题
Jackson
串行化java.time.Instant
与WRITE_DATE_TIMESTAMPS_AS_NANOSECONDS
默认启用。
它产生JSON
像这样
{ "timestamp":1421261297.356000000 }
我想知道是否有一种方法可以消除最后的零。我想要类似的东西:
{ "timestamp":1421261297.356 }
我试过了:
mapper.configure( SerializationFeature.WRITE_DATE_TIMESTAMPS_AS_NANOSECONDS, false );mapper.configure( SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, true );
但是此配置将其更改为毫秒表示1421261297356
。我想要秒部分和小数毫秒部分。
回答:
当我们使用Java 8
Time
package时,Jackson
最好使用jackson-modules-
java8项目,该项目可以使用许多序列化程序和反序列化程序。要启用它,我们需要注册JavaTimeModule
模块。要序列化Instant
InstantSerializer,请使用。当我们检查它的实现方式时,我们会发现在后台使用了DecimalUtils.toDecimal方法。看起来在纳秒值的末尾总是添加零。
我们可以编写InstantSerializer
以所需方式对其进行序列化的代码。由于该项目中的类尚未准备好轻松扩展,因此我们需要实现许多不需要的方法和构造函数。另外,我们需要在项目com.fasterxml.jackson.datatype.jsr310.ser
包中创建并在其中创建实现。请参见以下示例:
package com.fasterxml.jackson.datatype.jsr310.ser;import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.databind.SerializerProvider;
import java.io.IOException;
import java.math.BigDecimal;
import java.time.Instant;
import java.time.format.DateTimeFormatter;
import java.util.function.ToIntFunction;
import java.util.function.ToLongFunction;
public class ShortInstantSerializer extends InstantSerializerBase<Instant> {
private ToLongFunction<Instant> getEpochSeconds = Instant::getEpochSecond;
private ToIntFunction<Instant> getNanoseconds = i -> i.getNano() / 1_000_000;
public ShortInstantSerializer() {
super(Instant.class, Instant::toEpochMilli, Instant::getEpochSecond, Instant::getNano, null);
}
protected ShortInstantSerializer(ShortInstantSerializer base, Boolean useTimestamp, Boolean useNanoseconds, DateTimeFormatter formatter) {
super(base, useTimestamp, useNanoseconds, formatter);
}
@Override
protected JSR310FormattedSerializerBase<?> withFormat(Boolean useTimestamp, DateTimeFormatter formatter, JsonFormat.Shape shape) {
return new ShortInstantSerializer(this, useTimestamp, null, formatter);
}
@Override
public void serialize(Instant value, JsonGenerator generator, SerializerProvider provider) throws IOException {
if (useTimestamp(provider)) {
if (useNanoseconds(provider)) {
generator.writeNumber(new BigDecimal(toShortVersion(value)));
return;
}
}
super.serialize(value, generator, provider);
}
private String toShortVersion(final Instant value) {
return getEpochSeconds.applyAsLong(value) + "." + padWithZeros(getNanoseconds.applyAsInt(value));
}
private String padWithZeros(final int value) {
return String.format("%1$3s", String.valueOf(value)).replace(' ', '0');
}
}
并举例说明如何使用它:
import com.fasterxml.jackson.databind.ObjectMapper;import com.fasterxml.jackson.databind.SerializationFeature;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;
import com.fasterxml.jackson.datatype.jsr310.ser.ShortInstantSerializer;
import java.time.Instant;
public class JsonApp {
public static void main(String[] args) throws Exception {
JavaTimeModule javaTimeModule = new JavaTimeModule();
javaTimeModule.addSerializer(Instant.class, new ShortInstantSerializer());
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(javaTimeModule);
mapper.disable(SerializationFeature.INDENT_OUTPUT);
System.out.println(mapper.writeValueAsString(new Element()));
}
}
class Element {
private Instant timestamp = Instant.now();
public Instant getTimestamp() {
return timestamp;
}
public void setTimestamp(Instant timestamp) {
this.timestamp = timestamp;
}
}
上面的代码打印:
{"timestamp":1559074287.223}
如果要在所有情况下都消除全零,则编写您自己的getNanoseconds
在ShortInstantSerializer
类中声明的函数。
以上是 杰克逊将即时序列化为纳秒级问题 的全部内容, 来源链接: utcz.com/qa/408014.html