通过Selenium WebDriver验证列表元素

Z时代
2024-01-10
分类：问答

WebElement select = myD.findElement(By.xpath("//*[@id='custfoodtable']/tbody/tr[2]/td/div/select"));
List<WebElement> allOptions = select.findElements(By.tagName("option"));
for (WebElement option : allOptions) {
    System.out.println(String.format("Value is: %s", option.getAttribute("value")));
    option.click();
    Object vaLue = "Gram";
    if (option.getAttribute("value").equals(vaLue)) {
        System.out.println("Pass");
    } else {
        System.out.println("fail");
    }
}

我可以验证列表中的一个元素，但是下拉菜单中有20个元素需要验证，我不想使用上述逻辑20次。有没有更简单的方法可以做到？

回答：

不要使用for-each构造。仅在对单个Iterable/数组进行迭代时有用。您需要同时遍历List<WebElement>和数组。

// assert that the number of found <option> elements matches the expectations
assertEquals(exp.length, allOptions.size());
// assert that the value of every <option> element equals the expected value
for (int i = 0; i < exp.length; i++) {
    assertEquals(exp[i], allOptions.get(i).getAttribute("value"));
}

OP稍微改变了他的问题后进行编辑：

假设您有一组期望值，则可以执行以下操作：

String[] expected = {"GRAM", "OUNCE", "POUND", "MILLIMETER", "TSP", "TBSP", "FLUID_OUNCE"};
List<WebElement> allOptions = select.findElements(By.tagName("option"));
// make sure you found the right number of elements
if (expected.length != allOptions.size()) {
    System.out.println("fail, wrong number of elements found");
}
// make sure that the value of every <option> element equals the expected value
for (int i = 0; i < expected.length; i++) {
    String optionValue = allOptions.get(i).getAttribute("value");
    if (optionValue.equals(expected[i])) {
        System.out.println("passed on: " + optionValue);
    } else {
        System.out.println("failed on: " + optionValue);
    }
}