用联合mysql选择查询分组

  • Z时代
  • 2024-01-10
  • 分类：问答

(SELECT COUNT(motorbike.`owner_id`) as count,owner.`name`,transport.`type` FROM transport,owner,motorbike WHERE transport.type='motobike'
AND owner.`owner_id`=motorbike.`owner_id`
AND transport.`type_id`=motorbike.`motorbike_id` GROUP BY motorbike.owner_id)
UNION ALL
(SELECT COUNT(car.`owner_id`) as count,owner.`name`,transport.`type` FROM transport,owner,car WHERE transport.type='car'
AND owner.`owner_id`=car.`owner_id`
AND transport.`type_id`=car.`car_id` GROUP BY car.`owner_id`)

上面的查询返回如下结果，

count          name
1              Linda
2              Mary
1              Steve
1              Linda

此查询用于计算所有者拥有的传输数量。琳达有一辆汽车和一辆摩托车，所以结果应该是：

count          name
2              Linda
2              Mary
1              Steve

我已经尝试过此查询，但返回错误：

(SELECT COUNT(motorbike.`owner_id`),owner.`name`,transport.`type` FROM transport,owner,motorbike WHERE transport.type='motobike'
AND owner.`owner_id`=motorbike.`owner_id`
AND transport.`type_id`=motorbike.`motorbike_id`)
UNION ALL
(SELECT COUNT(car.`owner_id`),owner.`name`,transport.`type` FROM transport,owner,car WHERE transport.type='car'
AND owner.`owner_id`=car.`owner_id`
AND transport.`type_id`=car.`car_id`)  GROUP BY motorbike.owner_id

谁能帮我吗？

回答：

select sum(qty), name
from (
    select count(m.owner_id) as qty, o.name
    from transport t,owner o,motorbike m
    where t.type='motobike' and o.owner_id=m.owner_id
        and t.type_id=m.motorbike_id
    group by m.owner_id
    union all
    select count(c.owner_id) as qty, o.name,
    from transport t,owner o,car c
    where t.type='car' and o.owner_id=c.owner_id and t.type_id=c.car_id
    group by c.owner_id
) t
group by name

以上是 用联合mysql选择查询分组 的全部内容， 来源链接： utcz.com/qa/399202.html

回到顶部