如何将点击我的html文件的图像url传递给view.py中的python函数Django

  • Z时代
  • 2024-01-10
  • 分类：问答

我想传递用户在我的python函数views.py中选择的图像的url，因为我的python函数将处理用户选择的图像。这是我的HTML命令如何将点击我的html文件的图像url传递给view.py中的python函数Django

<!DOCTYPE html> 
<html> 
<head> 
<link class="jsbin" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" /> 
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> 
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.0/jquery-ui.min.js"></script> 
<meta charset=utf-8 /> 
<title>JS Bin</title> 
<!--[if IE]> 
    <script src="http://html5shiv.googlecode.com/svn/trunk/html5.js"></script> 
<![endif]--> 
<style> 
    article, aside, figure, footer, header, hgroup, 
    menu, nav, section { display: block; } 
</style> 
</head> 
<body> 
    <input type='file' onchange="readURL(this);" /> 
    <img id="blah" src="#" alt="your image" /> 
<script> 
    function readURL(input) { 
     if (input.files && input.files[0]) { 
      var reader = new FileReader(); 
      reader.onload = function (e) { 
       $('#blah') 
        .attr('src', e.target.result) 
        .width(150) 
        .height(200); 
      }; 
      reader.readAsDataURL(input.files[0]); 
     } 
    } 
</script> 
</body> 
</html>

这里是一个由用户选择必须在cv2.imread（）我怎样才能做到这一点对我的蟒蛇

def predict(): 
    img = cv2.imread('C:/Users/HABITUS/Desktop/arvin files/download.jpg') #the url of the image selected must be here!! 
    img = cv2.resize(img, (600, 600)) 
    enhancer = Image.fromarray(img) 
    enhancer = ImageEnhance.Contrast(enhancer) 
    enhanced = enhancer.enhance(1.5) 
    enhancer1 = ImageEnhance.Brightness(enhanced).enhance(1.3) 
    convert = scipy.misc.fromimage(enhancer1) 
    imgM = cv2.medianBlur(convert, 5) 
    # blurring and smoothening 
    kernel = np.ones((5, 5), np.uint8) 
    erosion = cv2.erode(imgM, kernel, iterations=1) 
    dilation = cv2.dilate(erosion, kernel, iterations=1) 
    blur = cv2.GaussianBlur(convert, (15, 15), 10) 
    grayscaled = cv2.cvtColor(imgM, cv2.COLOR_BGR2GRAY) 
    retval2, threshold2 = cv2.threshold(grayscaled, 200, 1, cv2.THRESH_BINARY_INV) 
    gaus = cv2.adaptiveThreshold(grayscaled, 255, cv2.ADAPTIVE_THRESH_GAUSSIAN_C, cv2.THRESH_BINARY, 115, 1) 
    retval2, otsu = cv2.threshold(grayscaled, 140, 250, cv2.THRESH_BINARY + cv2.THRESH_OTSU) 
    backtorgb = cv2.cvtColor(threshold2, cv2.COLOR_GRAY2RGB) 
    mult = cv2.multiply(img, backtorgb) 
    edges = cv2.Canny(threshold2, 120, 50)

图像的功能？任何意见或帮助将不胜感激

回答：

这有点混乱。

你可能要开始阅读 https://docs.djangoproject.com/en/2.0/topics/forms/

而且这里有两个存在的问题，应该帮助你：

  • Very simple user input in django

  • Need a minimal Django file upload example

以上是 如何将点击我的html文件的图像url传递给view.py中的python函数Django 的全部内容， 来源链接： utcz.com/qa/266402.html

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