加载AJAX数据插入

我试图插入数据到数据库使用PHP,但我不知道如何做到这一点,其实我有搜索谷歌,但没有适当的解决方案。加载AJAX数据插入

我的Ajax代码是:

if(window.location == "path/to/file") { 

$(window).on('load',function() {

var id = $("#id").val();

var cd = $("#cd").val();

var ed = $("#ed").val();

var status = $("#status").val();

if(ed == cd){

status = "Stopped";

console.log(status);

$.ajax({

type: "POST",

url: "wba.php",

data: "status=" + status,

success: function(data) {

alert("sucess");

}

});

}

else{

console.log('Running');

}

});

}

现在我不知道如何从AJAX获取数据,并使用PHP其插入到我的数据库和我的数据库表结构

INSERT into table_name(id, cd, ed, status) VALUES(); 

我的WBA.php文件代码在这个文件中提到,我从表中获取数据,然后当当前时间变成等于结束时间时,我希望此页面自动将广告的状态从运行状态更改为停止状态,并更新数据库中的值刷新页面,甚至没有点击任何屁股上。

<div id="main-content"> 

<div class="casteform">

<?php

$query = "SELECT * FROM advertisements WHERE ad_category = 'weddingbellsad'";

$run = mysqli_query($con, $query);

if(mysqli_num_rows($run) > 0){

while ($row = mysqli_fetch_assoc($run)) {

$ad_id = mysqli_real_escape_string($con, $row['ad_id']);

$ad_company = mysqli_real_escape_string($con, $row['ad_company']);

$ad_start_date = mysqli_real_escape_string($con, $row['ad_start_date']);

$ad_duration = mysqli_real_escape_string($con, $row['ad_duration']);

$ad_reminder_days = mysqli_real_escape_string($con, $row['ad_reminder_days']);

$ad_reminder_date = mysqli_real_escape_string($con, $row['ad_reminder_date']);

$ad_end_date = mysqli_real_escape_string($con, $row['ad_end_date']);

$ad_payment_method = mysqli_real_escape_string($con, $row['ad_payment_method']);

$ad_payment_amount = mysqli_real_escape_string($con, $row['ad_payment_amount']);

$ad_category = mysqli_real_escape_string($con, $row['ad_category']);

$ad_status = mysqli_real_escape_string($con, $row['ad_status']);

$ad_current_date = date('Y-m-d h:i:s');

?>

<div class="adrow">

<h4>Company Name: <?php echo $ad_company . " (" . $ad_id . ") "; ?> <small><?php echo $ad_status ?></small></h4>

<ul>

<li><span>Starting Date:</span> <?php echo $ad_start_date; ?></li>

<li><span>Duration:</span> <?php echo $ad_duration . " Days"; ?></li>

<li><span>Reminder:</span> <?php echo "Before ". $ad_reminder_days . " Day(s)"; ?></li>

<li><span>Reminder Date:</span> <?php echo $ad_reminder_date; ?></li>

<li><span>Ending Date:</span> <?php echo $ad_end_date; ?></li>

<li><span>Payment Method:</span> <?php echo $ad_payment_method; ?></li>

<li><span>Payment Amount:</span> <?php echo "Rs - " . $ad_payment_amount; ?></li>

<li><span>Ad Category:</span> <?php echo $ad_category; ?></li>

</ul>

<form>

<input type="text" id="id" value="<?php echo $ad_id; ?>" />

<input type="text" id="cd" value="<?php echo $ad_current_date; ?>" />

<input type="text" id="ed" value="<?php echo $ad_end_date; ?>" />

<input type="text" id="status" value="<?php echo $ad_status; ?>" />

</form>

</div>

<?php

}

}

else{

header("location: view-wedding-bell-ad.php?error=".urlencode("No advertisements found so far."));

exit();

}

?>

</div>

回答:

要通过Ajax传递多个值,则需要调整.ajax呼叫这样(注意data变化):在

$.ajax({ 

type: "POST",

url: "wba.php",

data: {

"id" : id,

"cd" : cd,

"ed" : ed,

"status" : status

},

success: function(data) {

alert("sucess");

}

});

,然后在PHP的身边你wba.php你在这些值得到:

$_POST['id'] 

$_POST['cd']

$_POST['ed']

$_POST['status']

至于所有其他数据库交互等,我们需要你自己尝试一下,找出你的目标和需要的结果。它有点宽泛,超出了StackOverflow的范围,因为别人现在可以为你编写所有这些。如果您需要进一步帮助,您随时可以提出其他问题以涵盖您遇到的具体问题。

但是重要的是:确保您使用“准备好的语句”!这将有助于保护您免受最常见的攻击媒介之一的侵害。

一个例子起动器(http://php.net/manual/en/mysqli-stmt.bind-param.php):

$stmt = $mysqli->prepare("INSERT into table_name(id, cd, ed, status) VALUES(?, ?, ?, ?)"); 

$stmt->bind_param('ssss', $_POST['id'], $_POST['cd'], $_POST['ed'], $_POST['status']);

$stmt->execute();

以上是 加载AJAX数据插入 的全部内容, 来源链接: utcz.com/qa/266294.html

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