动态获取阵列所有元素的所有组合

  • Z时代
  • 2024-01-10
  • 分类：问答

重要提示： 您只能从每个阵列中选择一个元素。动态获取阵列所有元素的所有组合

我正在写代码，让我测试测验排列。下面是我返回所有可能的排列数组的当前硬编码方式。我需要适应这是动态的，因为稍后会添加更多的数组。

我正在考虑一种方法，它可以接受一个选项数组，并返回一个排列数组，但是我的大脑在第一个循环后中断。任何帮助将非常感激。

options = 
[ 
    [["Geek", "Chef", "Supporter", "Fashionista"]], 
    [["0-1000", "1001-10000", "No limit"]], 
    [["Many", "For One"]] 
] 
def test_gifts(options) 
    options.each_with_index do |a,index| 
    .... 
    end 
end

硬编码的：

character_types = ["Geek","Chef", "Supporter", "Fashionista"] 
price_ranges = ["0-1,000","1,001-10000","No limit"] 
party_size  = ["Many", "For One"] 
permutations = [] 
character_types.each do |type| 
    price_ranges.each do |price| 
    party_size.each do |party| 
     permutations << [type, price, party] 
    end  
    end 
end

它返回

[["Geek", "0-1,000", "Many"], ["Geek", "0-1,000", "For One"], ["Geek", "1,001-10000", "Many"], ["Geek", "1,001-10000", "For One"], ["Geek", "No limit", "Many"], ["Geek", "No limit", "For One"], ["Chef", "0-1,000", "Many"], ["Chef", "0-1,000", "For One"], ["Chef", "1,001-10000", "Many"], ["Chef", "1,001-10000", "For One"], ["Chef", "No limit", "Many"], ["Chef", "No limit", "For One"], ["Supporter", "0-1,000", "Many"], ["Supporter", "0-1,000", "For One"], ["Supporter", "1,001-10000", "Many"], ["Supporter", "1,001-10000", "For One"], ["Supporter", "No limit", "Many"], ["Supporter", "No limit", "For One"], ["Fashionista", "0-1,000", "Many"], ["Fashionista", "0-1,000", "For One"], ["Fashionista", "1,001-10000", "Many"], ["Fashionista", "1,001-10000", "For One"], ["Fashionista", "No limit", "Many"], ["Fashionista", "No limit", "For One"]]

回答：

使用Array#product方法是：

character_types.product(price_ranges, party_size)

处理未知数量的其他阵列：

arrays_to_permute = [character_types, price_ranges, party_size] 
first_array, *rest_of_arrays = arrays_to_permute 
first_array.product(*rest_of_arrays)

以上是 动态获取阵列所有元素的所有组合 的全部内容， 来源链接： utcz.com/qa/265061.html

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