怎么判断每项orders里的id是否重复
怎么判断每项orders里的id是否重复
[{ id:'1',
name:1,
orders:[
{
id:'2',
name:1,
},
{
id:'2',
name:1,
}
]
},
{
id:'1',
name:1,
orders:[
{
id:'2',
name:1,
}
]
}]
回答:
let list = [{ id:'1',
name:1,
orders:[
{
id:'2',
name:1,
},
{
id:'2',
name:1,
}
]
},
{
id:'1',
name:1,
orders:[
{
id:'2',
name:1,
}
]
}];
list.every(item=>{
let ids =item.orders.map(order=>order.id)
return new Set(ids).size==ids.length
});
结果 false
回答:
const data = [ {
id: "1",
name: 1,
orders: [
{
id: "2",
name: 1,
},
{
id: "2",
name: 1,
},
],
},
{
id: "1",
name: 1,
orders: [
{
id: "2",
name: 1,
},
],
},
];
const result = [];
// 数组项是否重复
const isRepeat = (arr) => {
const hash = {};
const result = arr.some((item) => {
if (hash[item]) {
return true;
} else {
hash[item] = true;
return false;
}
});
return result;
};
data.forEach((item, index) => {
result.push(isRepeat(item.orders));
});
// [ true, false ] true表示有重复项,false表示没有重复项
console.log(result);
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