两个数组对象去重并且根据第一个数据生成一个新的对象？
各位大佬，我想请问一下我想通过一个数组对象处理另外一个数组对象。生成一个新的数组对象要怎么处理？我想通过两个时间的字段做判断，给新生成的数组对象里面属性的值加上一个1。怎么写都不对。生成的都是有问题的。
通过的数组对象
thisDate: [{ date: "12",
prop: "twelve"
},{
date: "13",
prop: "thirteen"
},{
date: "14",
prop: "fourteen"
},{
date: "15",
prop: "fifteen"
},{
date: "16",
prop: "sixteen"
},{
date: "17",
prop: "seventeen"
},{
date: "18",
prop: "eighteen"
}],
想要处理的数组对象
data: [{ "DATE": "2023-09-04 15:33:54.0",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 16:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 17:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 18:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 19:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 20:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 21:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 22:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 23:00:00",
"ROOMNAME": "测试会议室1",
"ROOMID": "001"
}, {
"DATE": "2023-09-04 14:53:42.0",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 15:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 16:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 17:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 18:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 19:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}, {
"DATE": "2023-09-04 20:00:00",
"ROOMNAME": "会议室2222",
"ROOMID": "002"
}]
我的思路有问题想不出来了，写的代码不对生成的有问题。
let list = []; for (let i = 0; i < data.length; i++) {
let nextIndex = i + 1
let nextEle = data[nextIndex]
if (nextIndex < data.length) {
if (data[i].ROOMNAME != nextEle.ROOMNAME) {
let objData = {
name: nextEle.ROOMNAME,
}
for (let a = 0; a < _this.thisDate.length; a++) {
if (data[i].DATE.slice(11, 13) == _this.thisDate[a].date) {
objData[_this.thisDate[a].prop] = '1';
} else {
objData[_this.thisDate[a].prop] = '';
}
}
list.push(objData)
}
}
}
console.log('生成新的数组对象');
console.log(list);
我希望的是生成新的数组对象，合并同名，并且根据thisDate生成新的属性。在和data这个json判断时间对等的属性赋值1。
最后希望生成的格式格式是：
[{ ROOMNAME: '测试会议室',
twelve: '',
thirteen: '',
fourteen: '',
fifteen: '',
sixteen: '1',
seventeen: '1',
eighteen:'1',
},{
ROOMNAME: '会议室2222',
twelve: '',
thirteen: '',
fourteen: '1',
fifteen: '1',
sixteen: '1',
seventeen: '1',
eighteen:'1',
}]
回答：
如果没有看错的话，就是记录一下各会议室在某个小时段是否有开会。说一下解法。
前两个数据是一样的：
const thisDate = [ {
date: "12",
prop: "twelve",
},
{
date: "13",
prop: "thirteen",
},
{
date: "14",
prop: "fourteen",
},
{
date: "15",
prop: "fifteen",
},
{
date: "16",
prop: "sixteen",
},
{
date: "17",
prop: "seventeen",
},
{
date: "18",
prop: "eighteen",
},
];
const data = [ {
DATE: "2023-09-04 15:33:54.0",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 16:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 17:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 18:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 19:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 20:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 21:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 22:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 23:00:00",
ROOMNAME: "测试会议室1",
ROOMID: "001",
},
{
DATE: "2023-09-04 14:53:42.0",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 15:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 16:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 17:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 18:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 19:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
{
DATE: "2023-09-04 20:00:00",
ROOMNAME: "会议室2222",
ROOMID: "002",
},
];
使用哈希表做一个前置处理，根据会议室名称进行分组，其值为该会议室开会的小时。
注意，此处比较随意。若是严谨一点，应当使用ROOMID作为key，value也应当使用Set作为容器，以免数据量大导致的重复问题。
const map = new Map();for (const { DATE, ROOMNAME } of data) {
map.set(ROOMNAME, [...(map.get(ROOMNAME) ?? []), DATE.slice(11, 13)]);
}
最后遍历哈希表，与 thisDate 对照一下，即可得到结果：
const list = [];for (const [k, v] of map.entries()) {
const obj = {
name: k,
};
for (const { prop, date } of thisDate) {
obj[prop] = v.includes(date) ? "1" : "";
}
list.push(obj);
}
console.log("生成新的数组对象");
console.log(list);
结果如下：
生成新的数组对象[
{
name: '测试会议室1',
twelve: '',
thirteen: '',
fourteen: '',
fifteen: '1',
sixteen: '1',
seventeen: '1',
eighteen: '1'
},
{
name: '会议室2222',
twelve: '',
thirteen: '',
fourteen: '1',
fifteen: '1',
sixteen: '1',
seventeen: '1',
eighteen: '1'
}
]
以上是 两个数组对象去重并且根据第一个数据生成一个新的对象？ 的全部内容， 来源链接： utcz.com/p/934874.html
