shell打印给定日期的日历

Z时代
2024-01-10
分类：IT

学习shell有一段时间了，一直没有机会练手，看到同事发了一张照片，控制台显示了当月的日历，是用Python实现的，感觉挺好玩，所以准备用shell来实现一个，搞了一下午，终于搞定。

打印本月的日期


#! /bin/bash
#设置字体颜色
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"
#计算各个日期
month=`date +%m`
day=`date +%d`
year=`date +%Y`
weekday=`date -d "$year-$month-01" +%w`
nextmonth=`expr $month + 1`
today=`date +%d`
#计算本月有多少天
differ=$(( ($(date -d "$year-$nextmonth-01" +%s) - $(date +%s))/(24*60*60) )) 
days=`expr $differ + $day`
#打印标题
echo -en "${menucolor}"
echo -en "\t  $year $month\n"
echo "SUN MON TUE WEN THU FRI SAT"
echo -en "${start}"
#打印空格
if [ $weekday -ne 0 ];then
for((i=1;i<=$weekday;i++))
do
  echo -n "  "
  echo -n " "
done
fi
#打印日期
for((i=1;i<=$days;i++))
do
  printf "%s" " "
  echo -en "${tiffcolor}"
  #今天高亮显示
    if [ $today -eq $i ];then
      echo -en "${todaycolor}"
    fi
  printf "%2d" $i
  echo -en "${start}"
  echo -en " "
  if [ $((($weekday+$i)%7)) == 0 ];then
    echo ""
  fi
#  printf "%3d " $i
done
echo ""

执行结果：

扩展：给定任意日期，打印当月的日期


#! /bin/bash
#date=$1
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"
if [ $# -ne 1 ];then
  echo "plz input the date"
  exit 1
fi
date=$1
count=`echo $date |grep -o '-'|wc -l`
if [ $count -ne 2 ];then
  echo "plz input correct date"
  exit 1
fi
year=`echo $date|cut -d "-" -f 1`
month=`echo $date|cut -d "-" -f 2`
day=`echo $date|cut -d "-" -f 3`
expr $year + $month + $day + 0 &>/dev/null
if [ $? -ne 0 ];then
  echo "plz input a correct date"
  exit 1
elif [ $month -gt 12 -o $month -eq 0 ];then
  echo "plz input the month between 1 and 12"
  exit 1
elif [ $day -gt 31 -o $day -eq 0 ];then
  echo "plz input the day between 1 and 31"
  exit 1
fi
#nextmonth=$(( $month + 1))
#month=`date -d "$date" +%m`
#day=`date -d "$date" +%d`
#year=`date -d "$date" +%Y`
weekday=`date -d "$year-$month-01" +%w`
if [ $month -eq 12 ];then
  newmonth=1
  newyear=`expr $year + 1`
else
  newyear=$year
  #nextmonth= expr $month + 1
  newmonth=`expr $month + 1`
fi
days=$(( ($(date -d "${newyear}-${newmonth}-01" +%s) - $(date -d "$year-$month-01" +%s))/(24*60*60) )) 
#echo $days
echo -en "${menucolor}"
echo -en "\t  $year $month\n"
echo "SUN MON TUE WEN THU FRI SAT"
echo -en "${start}"
if [ $weekday -ne 0 ];then
for((i=1;i<=$weekday;i++))
do
  echo -n "  "
  echo -n " "
done
fi
for((i=1;i<=$days;i++))
do
  printf "%s" " "
  echo -en "${tiffcolor}"
    if [ $day -eq $i ];then
      echo -en "${todaycolor}"
    fi
  printf "%2d" $i
  echo -en "${start}"
  echo -en " "
  if [ $((($weekday+$i)%7)) == 0 ];then
    echo ""
  fi
#  printf "%3d " $i
done
echo ""