error: expected template-name before '<' token

• Z时代
• 2024-01-10
• 分类：IT

我采用的Linux系统gcc编译器，编译程序的时候出现"error: expected template-name before '<' token",自己搞不懂是哪里出了问题，非常感谢。代码粘贴的有点多，望见谅。

相关代码

    // 文件test.c++
    #include <iostream>
    #include "List/LList.h"
    using namespace std;
    #include    <stdlib.h>
    int
    main ( int argc, char *argv[] ) {
        LList<int> list;
        for (int i = 1; i <= 10; i ++)
        {
            list.append(i);
        }
        cout << "size of first: " << alist.length() << endl;
         return EXIT_SUCCESS;
    }
    // 文件LList.h
    #include<assert.h>
    #include<iostream>
    #define defaultSize 100
    using namespace std;
    // Singly linked list node
    template <typename E> 
    class Link {
    public:
        E element;
        Link *next;
        Link(const E& elemval, Link *nextval = NULL) {
            element = elemval;
            next = nextval;
        }
        Link(Link* nextval = NULL) {
            next = nextval;
        }
    };
    // Linked List implementation
    template <typename E>
    class LList: public List<E> {
    private:
        Link<E>* head;
        Link<E>* tail;
        Link<E>* curr;
        int cnt;
        void init() {
            curr = tail = head = new Link<E>;
            cnt = 0;
        }
        void removeall() {
            while(head != NULL) {
                curr = head;
                head = head->next;
                delete curr;
            }
        }
    public:
        // Constructor
        LList(int size = defaultSize) { init(); }
        // Destructor
        ~LList() { removeall(); }
        // Print list contents
        void print() const;
        // Clear list;
        void clear() { removeall();init(); }
        // Insert "it" at current position
        void insert(const E& it) {
            curr->next = new Link<E>(it, curr->next);
            if(tail == curr) tail = curr->next;
            cnt ++;
        }
        // Append "it" to list
        void append(const E& it) {
            tail = tail->next = new Link<E>(it, NULL);
            cnt ++;
        }
        // Remove and return current element
        E remove() {
            Assert(curr->next != NULL &&  "No element");
            // Remember value
            E it = curr->next->element;
            // Remember link node
            Link<E> *ltemp = curr->next;
            // Reset tail
            if(tail == curr->next) tail = curr;
            // Remove from list
            curr->next = curr->next->next;
            // Reclaim space
            delete ltemp;
            cnt --;
            return it;
        }
        // Put curr at start of list
        void moveToStart() {
            curr = head;
        }
        // Put curr at end of list
        void moveToEnd() {
            curr = tail;
        }
        // Put curr one step at left, no change if already at front
        void prev() {
            if(curr == head) return;
            Link<E>* temp = head;
            while(temp->next != curr) temp = temp->next;
            curr = temp;
        }
        // Move curr one step at right, nochange if already at last
        void next() {
            if(curr != tail) curr = curr->next;
        }
        // Return length
        int length() const { return cnt; }
        // Return position of current element
        int currPos() const {
            Link<E>* temp = head;
            int i;
            for(i = 0; curr != temp; i ++) {
                temp = temp->next;
            }
            return i;
        }
        // Move current to "pos"
        void moveToPos(int pos) {
            Assert((pos >= 0) && (pos <= cnt) && "Position out of range");
            curr = head;
            for(int i = 0; i < pos; i ++) curr = curr->next;
        }
        // Return current value
        const E& getValue() const {
            Assert(curr->next != NULL && "No value");
            return curr->next->element;
        }
    };

报错信息

    // Linked List implementation
    template <typename E>
    class LList: public List<E> {

代码这里编译出现错误:error: expected template-name before '<' token

相关截图

自己已经百度相关template相关解答。

回答：

class LList: public List {
这里的List没有定义吧

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