用Java发get请求响应不正确

  • Z时代
  • 2024-01-10
  • 分类：IT

我现在要封装网页版微信客户端的接口。在封装获取联系人列表的方法里面，我要通过get请求把参数发出去，请求网址如下：

https://wx.qq.com/cgi-bin/mmwebwx-bin/webwxgetcontact?pass_ticket=w4mJvFCkNL8jhdqd5gFscDcClX0eBrV%2FkkIsE%2FrEDqfIWpO%2BEIpEepo77M6E87OZ&r=1525134953248&seq=0&skey=@crypt_dfce2a98_7dc1c34a13beb53387ca0f2cbbf14617

然后获得如下的响应
图片描述

可是当我代码这样写的时候：

final long l = System.currentTimeMillis();//返回当前的计算机时间
String res = Http.sendGet("https://wx.qq.com/cgi-bin/mmwebwx-bin/webwxgetcontact","pass_ticket="+pass_ticket+"&r="+l+"&seq=0&skey="+skey);

返回的结果却是这样的：

{"BaseResponse": {"Ret": 1,"ErrMsg": ""},"MemberCount": 0,"MemberList": [],"Seq": 0}

请问我哪里写错了，我用的get方法是这样的

public static String sendGet(String url, String param) {
        String result = "";
        BufferedReader in = null;
        try {
            String urlNameString = url + "?" + param;
            URL realUrl = new URL(urlNameString);
            // 打开和URL之间的连接
            URLConnection connection = realUrl.openConnection();
            // 设置通用的请求属性
            connection.setRequestProperty("accept", "*/*");
            connection.setRequestProperty("connection", "Keep-Alive");
            connection.setRequestProperty("user-agent",
                    "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1;SV1)");
            // 建立实际的连接
            connection.connect();
            // 获取所有响应头字段
            Map<String, List<String>> map = connection.getHeaderFields();
            // 遍历所有的响应头字段
            for (String key : map.keySet()) {
                System.out.println(key + "--->" + map.get(key));
            }
            // 定义 BufferedReader输入流来读取URL的响应
            in = new BufferedReader(new InputStreamReader(
                    connection.getInputStream()));
            String line;
            while ((line = in.readLine()) != null) {
                result += line;
            }
        } catch (Exception e) {
            System.out.println("发送GET请求出现异常！" + e);
            e.printStackTrace();
        }
        // 使用finally块来关闭输入流
        finally {
            try {
                if (in != null) {
                    in.close();
                }
            } catch (Exception e2) {
                e2.printStackTrace();
            }
        }
        return result;
    }

回答：

String res = Http.sendGet("https://wx.qq.com/cgi-bin/mmwebwx-bin/webwxgetcontact","pass_ticket="+pass_ticket+"&r="+l+"&seq=0&skey"+skey);

最后skey少个等号

String res = Http.sendGet("https://wx.qq.com/cgi-bin/mmwebwx-bin/webwxgetcontact","pass_ticket="+pass_ticket+"&r="+l+"&seq=0&skey="+skey);

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