怎么将json 对象的里面的value 值 形成一个新的对象json对象 然后传给后端 ？

• Z时代
• 2024-01-10
• 分类：技术分享

例如：
源数据：let oldList=[{code:2001,name:张三，}{code:2002,name:李四，
},{code:2003,name:王五，}]

期望得到： let newList=[{code:2001,2002,2003}]

回答

let oldList=[{code:2001,name:'张三'},{code:2002,name:'李四'},{code:2003,name:'王五'}]
const list = oldList.map(item => { return { code: item.code } });
console.log(JSON.stringify(list));

可参考：

    let oldList = [{ code: 2001, name: '张三' },
        { code: 2002, name: '李四' },
        { code: 2003, name: '王五' }]
    let codeAll = oldList.reduce((prev, item) => {
        prev.push(item.code)
        return prev
    }, [])
    let newList = [{ code: codeAll.join(',') }]
    console.log('newList==>', newList)

var newList = [{
    code:  [{code:2001,name:'张三'},{code:2002,name:'李四'},{code:2003,name:'王五'}].map(({ code }) => code).join(',')
}]

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