java http get方式请求失败

Z时代
2024-01-10
分类：技术分享

代码很简单，就是发送一个get请求。

url是没问题的，手动打开获取数据，格式是这样的：

{"msg":"success","code":0,"money":0.02,"maxCode":40,"token":"BAA8FE9AD2B0B5E04A3832D8B7505B96A3C9"}

但是用代码请求一直不成功，conn.getResponseCode() 根本获取不到状态码。

根本想不明白什么原因。今天我发现写的其他get请求都没成功，以前写的可以

try {
URL url=new URL("http://www.huli667.com:81/sms/api/login?username=api-ArIGbJDn&password=a411724");
HttpURLConnection conn=(HttpURLConnection) url.openConnection();
conn.setConnectTimeout(5000);
conn.setRequestMethod("GET");
int code=conn.getResponseCode();
if(code==200){
InputStream in=conn.getInputStream();
String result=ParseStream.readInputStream(in);
System.out.println(result);
}
} catch (MalformedURLException e) {
} catch (ProtocolException e) {
} catch (IOException e) {
}

回答

 public static void main(String[] args) {
        try {
            URL url=new URL("http://www.huli667.com:81/sms/api/login?username=api-ArIGbJDn&password=a411724");
            HttpURLConnection conn=(HttpURLConnection) url.openConnection();
            conn.setConnectTimeout(5000);
            conn.setRequestMethod("GET");
            conn.setRequestProperty("User-Agent","Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36");
            int code=conn.getResponseCode();
            if(code==200){
                String res = "",line="";
                InputStream in=conn.getInputStream();
                BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(in,"UTF-8"));
                while( (line = bufferedReader.readLine()) != null )
                {
                    res += line;
                }
                System.out.println(res);
                bufferedReader.close();
                in.close();
            }
            conn.disconnect();
        } catch (Exception e){
            e.printStackTrace();
        }
    }