opencv腐蚀操作：让圆腐蚀后不变形依旧保持圆形？

Z时代
2024-01-10
分类：技术分享

代码：

import cv2 as cv

import numpy as np

pie=cv.imread('d:/pic/pie.png')

kernel=np.ones((7,7),np.uint8)

dilate=cv.dilate(pie,kernel,iterations=10)

erosion=cv.erode(pie,kernel,iterations=10)

res=np.hstack((pie,dilate,erosion))

cv.imshow('res',res)

cv.waitKey(0)

cv.destroyAllWindows()

结果：图片说明

回答

这个原因是对于圆形的物体使用正方形的核去做膨胀和腐蚀就会变的像四边形，只要修改kernel变成圆形就好了；

import cv2 as cv
    import numpy as np
    import math
    pie = cv.imread('0000.png')
    kernel = np.ones((7, 7), np.uint8)
    kernel_re = []
    rows, cols = kernel.shape
    for i in range(rows):
        result = [0 if math.sqrt((i-3)**2+(j-3)**2) > 3 else 1 for j in range(cols)]
        kernel_re.append(result)
    kernel_re = np.array(kernel_re, np.uint8)
    print(kernel_re, kernel)
    print(type(kernel_re), type(kernel))
    print(kernel_re.shape, kernel.shape)
    dilate = cv.dilate(pie, kernel, iterations=10)
    erosion = cv.erode(pie, kernel_re, iterations=10)
    res = np.hstack((pie, dilate, erosion))
    cv.imshow('res', res)
    cv.waitKey(0)
    cv.destroyAllWindows()