用Python matplot 绘制五角星平面

构建五个外点和五个内点，向内延伸就好。看了你的图例，越外圈，精度越低，那么效果是这样

以下是代码

# -*- coding: utf-8 -*-
"""
Created on Thu Sep 18 10:55:00 2020
@author: Eikoh
"""
import numpy as np
import math
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
ax = plt.subplot(111, projection='3d')  # 创建一个三维的绘图工程
r = 100                     #五角星顶点距离中心距离
v = 4                       #
l = math.floor(r / v)
parr = [0,1,2,3,4]
for j in range(l):
    data = [[],[],[]]
    #5个外点 5个内点
    for i in range(len(parr)):
        data[0].append(math.cos(math.pi * 0.4 * parr[i]) * r)
        data[1].append(math.sin(math.pi * 0.4 * parr[i]) * r)
        data[2].append(1)
        R = r * math.sin(math.pi * 0.1)/math.sin(math.pi * 0.2)
        data[0].append(math.cos(math.pi * 0.4 * parr[i] + math.pi * 0.2) * R)
        data[1].append(math.sin(math.pi * 0.4 * parr[i] + math.pi * 0.2) * R)
        data[2].append(1)
    r = r - v
    if r <= 0:
        break
    tdt = [[],[],[]]
    #边 散点
    for i in range(len(data[0])):
        cur = i
        if i == len(data[0]) - 1:
            nex = 0
        else:
            nex = i + 1  
        k = (data[1][nex] - data[1][cur]) / (data[0][nex] - data[0][cur])
        b = data[1][nex] - k * data[0][nex]
        xs = np.arange(data[0][cur],data[0][nex],(data[0][nex] - data[0][cur]) / 20)        #每条边由20个散点组成
        xs = xs[1:len(xs)]
        xy = []
        for j in range(len(xs)):
            tdt[0].append(xs[j])
            tdt[1].append(k * xs[j] + b)
            tdt[2].append(1)
    x, y, z = data[0],data[1],data[2]       #r间距下的10个顶点
    ax.scatter(x[:len(x)], y[:len(y)], z[:len(z)], c='b',s=1)  # 绘制数据点
    x, y, z = tdt[0],tdt[1],tdt[2]          #r间距下的所有边
    ax.scatter(x[:len(x)], y[:len(y)], z[:len(z)], c='b',s=1)  # 绘制数据点
ax.set_zlabel('Z')  # 坐标轴
ax.set_ylabel('Y')
ax.set_xlabel('X')
plt.show()