python中的 @ 修饰符

python

今天学习廖老师的python教程,碰到了修饰符'@',不太了解,查看了下官方文档。

简单的整理下:

@dec2

@dec1

def func(arg1, arg2, ...):

pass

 等价于

def func(arg1, arg2, ...):

pass

func = dec2(dec1(func))

使用示例:

 在comp.lang.python 和 python-dev的大部分讨论集中在更简捷地使用内置修饰符staticmethod() 和 classmethod() 上。但修饰符的功能远比这强大。下面会对它的使用进行一些讲解:

1.定义一个执行即退出的函数。注意,这个函数并不像通常情况那样,被真正包裹。

def onexit(f):

import atexit

atexit.register(f)

return f

@onexit

def func():

...

(Note that this example is probably not suitable for real usage, but is for example purposes only.)

注意,这个示例可能并不能准确表达在实际中的使用,它只是做一个示例。

2.定义一个只能产生一个实例的类(有实例后,这个类不能再产生新的实例)。注意,一旦这个类失效了(估计意思是保存在下文的singleton中字典中的相应键失效),就会促使程序员让这个类产生更多的实例。(来自于python-dev的Shane Hathaway)

def singleton(cls):

instances = {}

def getinstance():

if cls not in instances:

instances[cls] = cls()

return instances[cls]

return getinstance

@singleton

class MyClass:

...

3.Add attributes to a function. (Based on an example posted by Anders Munch on python-dev.)

def attrs(**kwds):

def decorate(f):

for k in kwds:

setattr(f, k, kwds[k])

return f

return decorate

@attrs(versionadded="2.2",

author="Guido van Rossum")

def mymethod(f):

...

4.Enforce function argument and return types. Note that this copies the func_name attribute from the old to the new function. func_name was made writable in Python 2.4a3:

def accepts(*types):

def check_accepts(f):

assert len(types) == f.func_code.co_argcount

def new_f(*args, **kwds):

for (a, t) in zip(args, types):

assert isinstance(a, t), \

"arg %r does not match %s" % (a,t)

return f(*args, **kwds)

new_f.func_name = f.func_name

return new_f

return check_accepts

def returns(rtype):

def check_returns(f):

def new_f(*args, **kwds):

result = f(*args, **kwds)

assert isinstance(result, rtype), \

"return value %r does not match %s" % (result,rtype)

return result

new_f.func_name = f.func_name

return new_f

return check_returns

@accepts(int, (int,float))

@returns((int,float))

def func(arg1, arg2):

return arg1 * arg2

5.Declare that a class implements a particular (set of) interface(s). This is from a posting by Bob Ippolito on python-dev based on experience with PyProtocols [27].

def provides(*interfaces):

"""

An actual, working, implementation of provides for

the current implementation of PyProtocols. Not

particularly important for the PEP text.

"""

def provides(typ):

declareImplementation(typ, instancesProvide=interfaces)

return typ

return provides

class IBar(Interface):

"""Declare something about IBar here"""

@provides(IBar)

class Foo(object):

"""Implement something here..."""

  

 

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