Swagger2匹配多个controller代码实例
方法一:使用多个controller的共同拥有的父类,即精确到两个controller的上一级
@Bean
public Docket createRestApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(apiInfo())
.select()
.apis(RequestHandlerSelectors.basePackage("com.shubing"))
.paths(PathSelectors.any())
.build();
}
方法二:指定所有controller的都实现的一个接口,比如@RestController
@Bean
public Docket createRestApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(apiInfo())
.select()
.apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
.paths(PathSelectors.any())
.build();
}
使用以下两种,都是错误的
@Bean
public Docket createRestApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(apiInfo())
.select()
.apis(RequestHandlerSelectors.basePackage("com.shubing.*.controller"))
.paths(PathSelectors.any())
.build();
}
@Bean
public Docket createRestApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(apiInfo())
.select()
.apis(RequestHandlerSelectors.basePackage("com.shubing.course.controller"))
.apis(RequestHandlerSelectors.basePackage("com.shubing.user.controller"))
.paths(PathSelectors.any())
.build();
}
以上是 Swagger2匹配多个controller代码实例 的全部内容, 来源链接: utcz.com/z/361350.html