MySQL的选择行,其中两列不具有相同的值?
您可以使用MySQL的!=运算符。语法如下:
SELECT *FROM yourTableNameWHERE yourColumnName1 !=yourColumnName2
OR (yourColumnName1 IS NULL AND yourColumnName2IS NOT NULL)
OR (yourColumnName2 IS NULL AND yourColumnName1 IS NOT NULL);
为了理解上述语法,让我们创建一个表。创建表的查询如下:
mysql> create table selectTwoColumns-> (
-> Id int NOT NULL AUTO_INCREMENT,
-> FirstNumber int,
-> SecondNumber int,
-> PRIMARY KEY(Id)
-> );
使用insert命令在表中插入一些记录。查询如下:
mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(10,20);mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(30,40);
mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(20,20);
mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(50,60);
mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(50,50);
mysql> insert into selectTwoColumns(FirstNumber,SecondNumber) values(70,NULL);
使用select语句显示表中的所有记录。查询如下:
mysql> select *from selectTwoColumns;
以下是输出:
+----+-------------+--------------+| Id | FirstNumber | SecondNumber |
+----+-------------+--------------+
| 1 | 10 | 20 |
| 2 | 30 | 40 |
| 3 | 20 | 20 |
| 4 | 50 | 60 |
| 5 | 50 | 50 |
| 6 | 70 | NULL |
+----+-------------+--------------+
6 rows in set (0.00 sec)
这是用于选择两列不具有相同值的行的查询:
mysql> select *from selectTwoColumns-> where FirstNumber!=SecondNumber
-> OR (FirstNumber IS NULL AND SecondNumber IS NOT NULL)
-> OR (SecondNumber IS NULL AND FirstNumber IS NOT NULL);
以下是输出:
+----+-------------+--------------+| Id | FirstNumber | SecondNumber |
+----+-------------+--------------+
| 1 | 10 | 20 |
| 2 | 30 | 40 |
| 4 | 50 | 60 |
| 6 | 70 | NULL |
+----+-------------+--------------+
4 rows in set (0.00 sec)
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