C程序比较两个矩阵是否相等
用户必须输入两个矩阵的顺序和两个矩阵的元素。然后,比较这两个矩阵。
如果矩阵元素和大小都相等,则显示两个矩阵相等。
如果矩阵的大小相等但元素不相等,则显示矩阵可以比较但不相等。
如果大小和元素不匹配,则显示无法比较矩阵。
程序
以下是比较两个矩阵是否相等的 C 程序-
#include <stdio.h>输出结果#include <conio.h>
main(){
int A[10][10], B[10][10];
int i, j, R1, C1, R2, C2, flag =1;
printf("Enter the order of the matrix A\n");
scanf("%d %d", &R1, &C1);
printf("Enter the order of the matrix B\n");
scanf("%d %d", &R2,&C2);
printf("Enter the elements of matrix A\n");
for(i=0; i<R1; i++){
for(j=0; j<C1; j++){
scanf("%d",&A[i][j]);
}
}
printf("Enter the elements of matrix B\n");
for(i=0; i<R2; i++){
for(j=0; j<C2; j++){
scanf("%d",&B[i][j]);
}
}
printf("MATRIX A is\n");
for(i=0; i<R1; i++){
for(j=0; j<C1; j++){
printf("%3d",A[i][j]);
}
printf("\n");
}
printf("MATRIX B is\n");
for(i=0; i<R2; i++){
for(j=0; j<C2; j++){
printf("%3d",B[i][j]);
}
printf("\n");
}
/* Comparing two matrices for equality */
if(R1 == R2 && C1 == C2){
printf("Matrices can be compared\n");
for(i=0; i<R1; i++){
for(j=0; j<C2; j++){
if(A[i][j] != B[i][j]){
flag = 0;
break;
}
}
}
}
else{
printf(" Cannot be compared\n");
exit(1);
}
if(flag == 1 )
printf("Two matrices are equal\n");
else
printf("But,two matrices are not equal\n");
}
执行上述程序时,会产生以下结果 -
Run 1:Enter the order of the matrix A
2 2
Enter the order of the matrix B
2 2
Enter the elements of matrix A
1
2
3
4
Enter the elements of matrix B
1
2
3
4
MATRIX A is
1 2
3 4
MATRIX B is
1 2
3 4
Matrices can be compared
Two matrices are equal
Run 2:
Enter the order of the matrix A
2 2
Enter the order of the matrix B
2 2
Enter the elements of matrix A
1
2
3
4
Enter the elements of matrix B
5
6
7
8
MATRIX A is
1 2
3 4
MATRIX B is
5 6
7 8
Matrices can be compared
But,two matrices are not equal
以上是 C程序比较两个矩阵是否相等 的全部内容, 来源链接: utcz.com/z/352641.html