Swift中字典与JSON转换的方法
Swift中经常会遇到字典和字符串的相互转换,因此可以转换可以封装起来,转换代码如下:
func convertStringToDictionary(text: String) -> [String:AnyObject]? {
if let data = text.data(using: String.Encoding.utf8) {
do {
return try JSONSerialization.jsonObject(with: data, options: [JSONSerialization.ReadingOptions.init(rawValue: 0)]) as? [String:AnyObject]
} catch let error as NSError {
print(error)
}
}
return nil
}
func convertDictionaryToString(dict:[String:AnyObject]) -> String {
var result:String = ""
do {
//如果设置options为JSONSerialization.WritingOptions.prettyPrinted,则打印格式更好阅读
let jsonData = try JSONSerialization.data(withJSONObject: dict, options: JSONSerialization.WritingOptions.init(rawValue: 0))
if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) {
result = JSONString
}
} catch {
result = ""
}
return result
}
func convertArrayToString(arr:[AnyObject]) -> String {
var result:String = ""
do {
let jsonData = try JSONSerialization.data(withJSONObject: arr, options: JSONSerialization.WritingOptions.init(rawValue: 0))
if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) {
result = JSONString
}
} catch {
result = ""
}
return result
}
实际测试:
let jsonText:String = "{\"order_info\":[{\"order_id\":\"1479828084819597144\",\"channel\":\"ios\",\"product_id\":\"02\"},{\"order_id\":\"1479828084819597144\",\"channel\":\"ios\",\"product_id\":\"02\"}]}"
let dict = self.convertStringToDictionary(text: jsonText)
print("字符串转换之后的字典:\(dict!)")
var dictionaryOrArray : [String: AnyObject] = [:]
dictionaryOrArray["a\"b"] = "cd" as AnyObject?
dictionaryOrArray["strings"] = ["string", "another"] as AnyObject?
dictionaryOrArray["keywdict"] = [ "anotherKey": 100, "Key2": "Val2"] as AnyObject?
dictionaryOrArray["numbers"] = [ 1, 2, 3] as AnyObject?
dictionaryOrArray["bools"] = [ true, false] as AnyObject?
let convertResult:String = self.convertDictionaryToString(dict: dictionaryOrArray)
print("字典转换之后的字符串:\(convertResult)")
let array:[String] = ["FlyElephant","keso"]
print("数组转换之后的数组:\(self.convertArrayToString(arr: array as [AnyObject]))")
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