C程序计算年龄
给定一个人的当前日期和出生日期,其任务是计算其当前年龄。
示例
Input-: present date-: 21/9/2019Birth date-: 25/9/1996
Output-: Present Age
Years: 22 Months:11 Days: 26
下面使用的方法如下-
输入一个人的当前日期和出生日期
检查条件
如果当前月份小于出生月份,那么我们将不考虑当前年份,因为今年尚未完成,因此通过在当前月份加上12来计算月份之间的差异。
如果当前日期小于出生日期,那么我们将不考虑月份,并且为了生成减法日期,请在当前日期上加上月数,结果日期将有所不同。
当满足此条件时,只需减去天,月和年即可得出最终结果
打印最终年龄
算法
StartStep 1-> declare function to calculate age
void age(int present_date, int present_month, int present_year, int birth_date, int birth_month, int birth_year)
Set int month[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }
IF (birth_date > present_date)
Set present_date = present_date + month[birth_month - 1]
Set present_month = present_month – 1
End
IF (birth_month > present_month)
Set present_year = present_year – 1
Set present_month = present_month + 12
End
Set int final_date = present_date - birth_date
Set int final_month = present_month - birth_month
Set int final_year = present_year - birth_year
Print final_year, final_month, final_date
Step 2-> In main() Set int present_date = 21
Set int present_month = 9
Set int present_year = 2019
Set int birth_date = 25
Set int birth_month = 9
Set int birth_year = 1996
Call age(present_date, present_month, present_year, birth_date, birth_month,
birth_year)
Stop
示例
#include <stdio.h>#include <stdlib.h>
//计算当前年龄的功能
void age(int present_date, int present_month, int present_year, int birth_date, int birth_month, int birth_year) {
int month[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
if (birth_date > present_date) {
present_date = present_date + month[birth_month - 1];
present_month = present_month - 1;
}
if (birth_month > present_month) {
present_year = present_year - 1;
present_month = present_month + 12;
}
int final_date = present_date - birth_date;
int final_month = present_month - birth_month;
int final_year = present_year - birth_year;
printf("Present Age Years: %d Months: %d Days: %d", final_year, final_month, final_date);
}
int main() {
int present_date = 21;
int present_month = 9;
int present_year = 2019;
int birth_date = 25;
int birth_month = 9;
int birth_year = 1996;
age(present_date, present_month, present_year, birth_date, birth_month, birth_year);
return 0;
}
输出结果
如果我们运行以上代码,它将在输出后产生
Present Age Years: 22 Months:11 Days: 26
以上是 C程序计算年龄 的全部内容, 来源链接: utcz.com/z/343523.html