python实现将列表中各个值快速赋值给多个变量

Z时代
2024-01-10
分类：综合

我就废话不多说啦，还是直接看代码吧！

list1 = [1,2,3,4]
a,b,c,d = list1

则

a = 1
b =2

等

这种方式只有当左边的操作数个数和list1长度相同时,才可以这么做,不然报错.

我们假设我们有一个list对象List,它的长度足够长,想把它从下标i开始的k个元素赋给k个元素,可以这么做:

v1, v2, v3, …, vk = List[i : i + k] #默认i=0, k=len(List)

补充知识：python 将某个字段存储为列表类型

实现存储数据格式为


{
    "_index": "nested-20180815",
    "_type": "stb-iptv-montor-m-gather-apk",
    "_id": "AWU8sZboGQQbsn0rAW4J",
    "_score": 1,
    "_source": {
     "mdiNested": [
      {
       "mdiMLR": 0,
       "mdiType": "0"
      },
      {
       "mdiMLR": 0,
       "mdiType": "1"
      },
      {
       "mdiMLR": 0,
       "mdiType": "2"
      },
      {
       "mdiMLR": 0,
       "mdiType": "3"
      },
      {
       "mdiMLR": 0,
       "mdiType": "4"
      },
      {
       "mdiMLR": 0,
       "mdiType": "5"
      }
     ]
    }
   }

代码：


from elasticsearch import Elasticsearch
from elasticsearch import helpers
import json
es_20 = Elasticsearch(hosts="1.0.0.0", port=9200, timeout=15000)
time_ = "20180815"
index_20 = "nested-{0}".format(time_)
type_20 = "stb-iptv-montor-m-gather-apk"
def set_mapping():
  my_mappping = {
    type_20: {
      "properties": {
        "mdiNested": {
          "properties": {
            "mdiMLR": {
              "type": "short"
            },
            "mdiType": {
              "type": "keyword"
            }
          }
        }
      }
    }
  }
  create_index = es_20.indices.create(index=index_20, body=None)
  create_mapping = es_20.indices.put_mapping(index=index_20, body=my_mappping, doc_type=type_20)
  mdiMLR = [0,1,2,3,4]
  mdiType = ["0","1","2","3","4","5"]
  actions = []
  dict_ ={}
  for mdiMLR_ in mdiMLR:
    dict_list = []
    for type in mdiType:
      t1 ={'mdiMLR': mdiMLR_, 'mdiType': type}
      dict_list.append(t1)
    action = {
        "_index": index_20,
        "_type": type_20,
        "_source": {
          "mdiNested": dict_list
        }
    }
    actions.append(action)
  helpers.bulk(es_20, actions)