MySQL查询以获取不包含空格的字段值?
为此使用“不喜欢”。让我们首先创建一个表-
mysql> create table DemoTable(
Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
StudentFullName varchar(40)
);
使用插入命令在表中插入记录-
mysql> insert into DemoTable(StudentFullName) values('JohnSmith');mysql> insert into DemoTable(StudentFullName) values('John Doe');
mysql> insert into DemoTable(StudentFullName) values('Adam Smith');
mysql> insert into DemoTable(StudentFullName) values('CarolTaylor');
使用select语句显示表中的所有记录-
mysql> select * from DemoTable;
这将产生以下输出-
+----+-----------------+| Id | StudentFullName |
+----+-----------------+
| 1 | JohnSmith |
| 2 | John Doe |
| 3 | Adam Smith |
| 4 | CarolTaylor |
+----+-----------------+
4 rows in set (0.00 sec)
以下是获取不包含空格的字段值的查询-
mysql> select *from DemoTable where StudentFullName NOT LIKE '% %';
这将产生以下输出-
+----+-----------------+| Id | StudentFullName |
+----+-----------------+
| 1 | JohnSmith |
| 4 | CarolTaylor |
+----+-----------------+
2 rows in set (0.18 sec)
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