vue.js实现只弹一次弹框
核心代码是 getCookie()部分,控制弹框的显示隐藏则在 created()中。
<template>
<div v-if="isShow"> <!--最外层背景-->
<div class="popup_container"> <!--居中的容器-->
<img @click="noPopup" src="delete.png" alt=""> <!--关闭弹框-->
<div class="popup_text"> <!--内容部分-->
Lorem ipsum dolor sit amet, consectetur adipisicing elit. At, atque ea eveniet laudantium magni, maiores nam nihil non numquam odio pariatur perferendis placeat quas quasi sit soluta, sunt ullam voluptatibus.
</div>
</div>
</div>
</template>
<script>
export default {
data(){
return{
isShow: true,
}
},
created(){
if (this.getCookie('popped') == ''){ //cookie 中没有 popped 则赋给他一个值(此时弹框显示)
document.cookie = "popped = yes";
}else{
this.isShow = false; //若cookie 中已经有 popped 值,则弹框再不会显示
}
},
methods: {
noPopup(){
this.isShow = false;
},
getCookie(Name) { //cookie
var search = Name + "=";
var returnValue = "";
if (document.cookie.length > 0) {
var offset = document.cookie.indexOf(search);
if (offset !== -1) {
offset += search.length;
var end = document.cookie.indexOf(";", offset);
if (end == -1){
end = document.cookie.length;
}
returnValue = decodeURIComponent(document.cookie.substring(offset, end));
}
}
return returnValue;
},
},
}
</script>
<style scoped>
/*样式部分*/
</style>
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