从MySQL的时间字段中删除秒?
您需要使用TIME_FORMAT()从时间字段中删除秒。语法如下:
SELECT TIME_FORMAT(yourColumnName1, "%H:%i") AS anyVariableName,TIME_FORMAT(yourColumnName2, "%H:%i") AS anyVariableName
FROM yourTableName;
为了理解上述语法,让我们创建一个表。创建表的查询如下:
mysql> create table removeSecondsFromTime-> (
-> Id int NOT NULL AUTO_INCREMENT,
-> StartTime time,
-> EndTime time,
-> PRIMARY KEY(Id)
-> );
使用insert命令在表中插入一些记录。查询如下:
mysql> insert into removeSecondsFromTime(StartTime,EndTime) values('10:20:45','11:21:40');mysql> insert into removeSecondsFromTime(StartTime,EndTime) values('12:30:55','13:20:21');
mysql> insert into removeSecondsFromTime(StartTime,EndTime) values('14:40:57','15:55:02');
使用select语句显示表中的所有记录。查询如下:
mysql> select *from removeSecondsFromTime;
以下是输出;
+----+-----------+----------+| Id | StartTime | EndTime |
+----+-----------+----------+
| 1 | 10:20:45 | 11:21:40 |
| 2 | 12:30:55 | 13:20:21 |
| 3 | 14:40:57 | 15:55:02 |
+----+-----------+----------+
3 rows in set (0.00 sec)
这是从时间字段中删除秒的查询:
mysql> select TIME_FORMAT(StartTime, "%H:%i") as StartingTime,-> TIME_FORMAT(EndTime, "%H:%i") as EndingTime
-> from removeSecondsFromTime;
以下是输出;
+--------------+------------+| StartingTime | EndingTime |
+--------------+------------+
| 10:20 | 11:21 |
| 12:30 | 13:20 |
| 14:40 | 15:55 |
+--------------+------------+
3 rows in set (0.00 sec)
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