如何将R数据帧的两列转换为命名向量?
如果两列的格式使得一列包含向量值的名称,而另一列具有向量值,则我们可能希望将它们转换为向量。为此,我们只需读取向量的数据类型并使用结构函数对其进行结构化即可。
例子1
x1<-rep(c("C1","C2","C3","C4"),each=5)x2<-rep(1:10,2)
df1<-data.frame(x1,x2)
df1
输出结果
x1 x21 C1 1
2 C1 2
3 C1 3
4 C1 4
5 C1 5
6 C2 6
7 C2 7
8 C2 8
9 C2 9
10 C2 10
11 C3 1
12 C3 2
13 C3 3
14 C3 4
15 C3 5
16 C4 6
17 C4 7
18 C4 8
19 C4 9
20 C4 10
df1_vector<-structure(as.numeric(df1$x2),names=as.character(df1$x1))
df1_vector
C1 C1 C1 C1 C1 C2 C2 C2 C2 C2 C3 C3 C3 C3 C3 C4 C4 C4 C4 C4
1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10
例子2
set.seed(111)y1<-LETTERS[1:20]
y2<-rnorm(20,0.5)
df2<-data.frame(y1,y2)
df2
输出结果
y1 y21 A 0.735220712
2 B 0.169264128
3 C 0.188376176
4 D -1.802345658
5 E 0.329123955
6 F 0.640278225
7 G -0.997426656
8 H -0.510188419
9 I -0.448475605
10 J 0.006037783
11 K 0.326325872
12 L 0.093401220
13 M 2.345636264
14 N 0.894054110
15 O 1.297528501
16 P -1.066665360
17 Q 0.414148991
18 R 0.140860519
19 S -0.693608967
20 T 0.864186737
df2_vector<-structure(as.numeric(df2$y2),names=as.character(df2$y1))
df2_vector
A B C D E F
0.735220712 0.169264128 0.188376176 -1.802345658 0.329123955 0.640278225
G H I J K L
-0.997426656 -0.510188419 -0.448475605 0.006037783 0.326325872 0.093401220
M N O P Q R
2.345636264 0.894054110 1.297528501 -1.066665360 0.414148991 0.140860519
S T
-0.693608967 0.864186737
例子3
z1<-rep(c("String1","String2","String3","String4","String5"),each=4)z2<-letters[20:1]
df3<-data.frame(z1,z2)
df3
输出结果
z1 z21 String1 t
2 String1 s
3 String1 r
4 String1 q
5 String2 p
6 String2 o
7 String2 n
8 String2 m
9 String3 l
10 String3 k
11 String3 j
12 String3 i
13 String4 h
14 String4 g
15 String4 f
16 String4 e
17 String5 d
18 String5 c
19 String5 b
20 String5 a
df3_vector<-structure(as.character(df3$z2),names=as.character(df3$z1))
df3_vector
String1 String1 String1 String1 String2 String2 String2 String2 String3 String3
"t" "s" "r" "q" "p" "o" "n" "m" "l" "k"
String3 String3 String4 String4 String4 String4 String5 String5 String5 String5
"j" "i" "h" "g" "f" "e" "d" "c" "b" "a"
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