Python新手实现2048小游戏

接触 Python 不久,看到很多人写2048,自己也捣鼓了一个,主要是熟悉Python语法。

程序使用Python3 写的,代码150行左右,基于控制台,方向键使用输入字符模拟。

演示图片

2048.py

# -*- coding:UTF-8 -*-

#! /usr/bin/python3

import random

v = [[0, 0, 0, 0],

[0, 0, 0, 0],

[0, 0, 0, 0],

[0, 0, 0, 0]]

def display(v, score):

'''显示界面

'''

print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))

print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))

print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))

print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), ' Total score: ', score)

def init(v):

'''随机分布网格值

'''

for i in range(4):

v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)]

def align(vList, direction):

'''对齐非零的数字

direction == 'left':向左对齐,例如[8,0,0,2]左对齐后[8,2,0,0]

direction == 'right':向右对齐,例如[8,0,0,2]右对齐后[0,0,8,2]

'''

# 移除列表中的0

for i in range(vList.count(0)):

vList.remove(0)

# 被移除的0

zeros = [0 for x in range(4 - len(vList))]

# 在非0数字的一侧补充0

if direction == 'left':

vList.extend(zeros)

else:

vList[:0] = zeros

def addSame(vList, direction):

'''在列表查找相同且相邻的数字相加, 找到符合条件的返回True,否则返回False,同时还返回增加的分数

direction == 'left':从右向左查找,找到相同且相邻的两个数字,左侧数字翻倍,右侧数字置0

direction == 'right':从左向右查找,找到相同且相邻的两个数字,右侧数字翻倍,左侧数字置0

'''

score = 0

if direction == 'left':

for i in [0, 1, 2]:

if vList[i] == vList[i+1] != 0:

vList[i] *= 2

vList[i+1] = 0

score += vList[i]

return {'bool':True, 'score':score}

else:

for i in [3, 2, 1]:

if vList[i] == vList[i-1] != 0:

vList[i-1] *= 2

vList[i] = 0

score += vList[i-1]

return {'bool':True, 'score':score}

return {'bool':False, 'score':score}

def handle(vList, direction):

'''处理一行(列)中的数据,得到最终的该行(列)的数字状态值, 返回得分

vList: 列表结构,存储了一行(列)中的数据

direction: 移动方向,向上和向左都使用方向'left',向右和向下都使用'right'

'''

totalScore = 0

align(vList, direction)

result = addSame(vList, direction)

while result['bool'] == True:

totalScore += result['score']

align(vList, direction)

result = addSame(vList, direction)

return totalScore

def operation(v):

'''根据移动方向重新计算矩阵状态值,并记录得分

'''

totalScore = 0

gameOver = False

direction = 'left'

op = input('operator:')

if op in ['a', 'A']: # 向左移动

direction = 'left'

for row in range(4):

totalScore += handle(v[row], direction)

elif op in ['d', 'D']: # 向右移动

direction = 'right'

for row in range(4):

totalScore += handle(v[row], direction)

elif op in ['w', 'W']: # 向上移动

direction = 'left'

for col in range(4):

# 将矩阵中一列复制到一个列表中然后处理

vList = [v[row][col] for row in range(4)]

totalScore += handle(vList, direction)

# 从处理后的列表中的数字覆盖原来矩阵中的值

for row in range(4):

v[row][col] = vList[row]

elif op in ['s', 'S']: # 向下移动

direction = 'right'

for col in range(4):

# 同上

vList = [v[row][col] for row in range(4)]

totalScore += handle(vList, direction)

for row in range(4):

v[row][col] = vList[row]

else:

print('Invalid input, please enter a charactor in [W, S, A, D] or the lower')

return {'gameOver':gameOver, 'score':totalScore}

# 统计空白区域数目 N

N = 0

for q in v:

N += q.count(0)

# 不存在剩余的空白区域时,游戏结束

if N == 0:

gameOver = True

return {'gameOver':gameOver, 'score':totalScore}

# 按2和4出现的几率为3/1来产生随机数2和4

num = random.choice([2, 2, 2, 4])

# 产生随机数k,上一步产生的2或4将被填到第k个空白区域

k = random.randrange(1, N+1)

n = 0

for i in range(4):

for j in range(4):

if v[i][j] == 0:

n += 1

if n == k:

v[i][j] = num

break

return {'gameOver':gameOver, 'score':totalScore}

init(v)

score = 0

print('Input:W(Up) S(Down) A(Left) D(Right), press <CR>.')

while True:

display(v, score)

result = operation(v)

if result['gameOver'] == True:

print('Game Over, You failed!')

print('Your total score:', score)

else:

score += result['score']

if score >= 2048:

print('Game Over, You Win!!!')

print('Your total score:', score)

以上所述就是本文给大家分享的全部代码了,希望能够对大家学习Python有所帮助。

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