JavaScript实现构造json数组的方法分析
本文实例讲述了JavaScript实现构造json数组的方法。分享给大家供大家参考,具体如下:
从后端拿到的数据是一个数组,每个元素中包含的数据如下(host相同的记录都是相邻的)
currentTime:"1470729601"
host:"10.3.34.21"
taskList:null
taskNum:1
想构造类似如下结构的json数组
[{
name: 'host:10.1.6.49',
data: [
[1470641461000, 5],
[1470642581000, 4],
[1470643701000, 2],
[1470647341000, 3]
]
}, {
name: 'host:10.3.34.18',
data: [
[1470641461000, 2],
[1470642581000, 2],
[1470643701000, 1],
[1470647341000, 4]
]
}, {
name: 'host:10.2.2.22',
data: [
[1470641461000, 3],
[1470642581000, 2],
[1470643701000, 6],
[1470647341000, 4]
]
},{
name: 'host:10.1.110.96',
data: [
[1470641461000, 1],
[1470642581000, 8],
[1470643701000, 1],
[1470647341000, 1]
]
},{
name: 'host:10.2.2.87',
data: [
[1470641461000, 7],
[1470642581000, 3],
[1470643701000, 6],
[1470647341000, 5]
]
}]
错误的方式:
var backendData = data.result;
var resultList = new Array();
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
var host = backendData[i].host;
if (host != curHost) {
if(i != 0) {
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
}
oneHostDataList = new Array();
curHost = host;
}
else {
var dot = new Array();
dot.push(backendData[i].currentTime * 1000);
dot.push(backendData[i].taskNum);
oneHostDataList.push(dot);
}
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = JSON.stringify(resultList);
以上方式的问题在于转换后会使得name和host和带上引号,正确的方式如下:
var backendData = data.result;
var resultList = [];
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
var host = backendData[i].host;
if (host != curHost) {
if(i != 0) {
var item = {
name: curHost,
data: oneHostDataList
};
resultList.push(item);
}
oneHostDataList = new Array();
curHost = host;
}
else {
var dot = new Array();
dot.push(backendData[i].currentTime * 1000);
dot.push(backendData[i].taskNum);
oneHostDataList.push(dot);
}
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = resultList;
PS:这里再为大家推荐几款相关的json在线工具供大家参考:
在线JSON代码检验、检验、美化、格式化工具:
http://tools.jb51.net/code/json
JSON在线格式化工具:
http://tools.jb51.net/code/jsonformat
在线XML/JSON互相转换工具:
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