如何在Python中合并两个json字符串?
我最近开始使用Python,并且尝试将我的JSON字符串之一与现有JSON字符串连接在一起。我也在与Zookeeper一起工作,所以当我使用Python
kazoo库时,我从zookeeper节点获取了现有的json字符串。
# gets the data from zookeeperdata, stat = zk.get(some_znode_path)
jsonStringA = data.decode("utf-8")
如果我打印,jsonStringA
它会给我这样的感觉-
{"error_1395946244342":"valueA","error_1395952003":"valueB"}
但是,如果我这样做,print json.loads(jsonString)
它会像这样打印出来-
{u'error_1395946244342': u'valueA', u'error_1395952003': u'valueB'}
这里jsonStringA
将有我现有的JSON字符串。现在我有另一个键值对,我需要在出口添加jsonStringA
-
以下是我的Python代码-
# gets the data from zookeeperdata, stat = zk.get(some_znode_path)
jsonStringA = data.decode("utf-8")
timestamp_in_ms = "error_"+str(int(round(time.time() * 1000)))
node = "/pp/tf/test/v1"
a,b,c,d = node.split("/")[1:]
host_info = "h1"
local_dc = "dc3"
step = "step2"
jsonStringA
从Zookeeper提取后,我的现有状态将如下所示:
{"error_1395946244342":"valueA","error_1395952003":"valueB"}
现在,我需要将此键值对添加到jsonStringA
-
"timestamp_in_ms":"Error Occured on machine "+host_info+" in datacenter "+ local_dc +" on the "+ step +" of process "+ c +"
简而言之,我需要合并以下键值对-
"error_1395952167":"Error Occured on machine h1 in datacenter dc3 on the step2 of process test"
因此,最终的JSON字符串将如下所示-
{"error_1395946244342":"valueA","error_1395952003":"valueB","error_1395952167":"Error Occured on machine h1 in datacenter dc3 on the step2 of process test"}
这可能吗?
回答:
假设a和b是要合并的字典:
c = {key: value for (key, value) in (a.items() + b.items())}
要将字符串转换为python字典,请使用以下命令:
import jsonmy_dict = json.loads(json_str)
# test cases for jsonStringA and jsonStringB according to your data inputjsonStringA = '{"error_1395946244342":"valueA","error_1395952003":"valueB"}'
jsonStringB = '{"error_%d":"Error Occured on machine %s in datacenter %s on the %s of process %s"}' % (timestamp_number, host_info, local_dc, step, c)
# now we have two json STRINGS
import json
dictA = json.loads(jsonStringA)
dictB = json.loads(jsonStringB)
merged_dict = {key: value for (key, value) in (dictA.items() + dictB.items())}
# string dump of the merged dict
jsonString_merged = json.dumps(merged_dict)
但是我不得不说,总的来说,您尝试做的并不是最佳实践。请阅读有关python词典的内容。
jsonStringA = get_my_value_as_string_from_somewhere()errors_dict = json.loads(jsonStringA)
new_error_str = "Error Ocurred in datacenter %s blah for step %s blah" % (datacenter, step)
new_error_key = "error_%d" % (timestamp_number)
errors_dict[new_error_key] = new_error_str
# and if I want to export it somewhere I use the following
write_my_dict_to_a_file_as_string(json.dumps(errors_dict))
实际上,如果仅使用数组来保存所有错误,则可以避免所有这些情况。
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